All categories

2 years ago

Point C,D and E are collinear on CE, and CD:DE = 3/5. C is located at (1,8), D is located (4,5), and E is located at (x,y)

Mathematics

1 answer:

Ugo [173]2 years ago

7 0

Point c and d are the xy factor

You might be interested in

Rearrange f=3g+2 to make g the subject

Helen [10]

Minus 2 from bothsides
f-2=3g
divide both sides by 3
(f-2)/3=g
g=(f-2)/3

6 0

4 years ago

Read 2 more answers

Can someone help me pls

KatRina [158]

Answer:

x=5

Step-by-step explanation:

x=5 hope this helps!

8 0

3 years ago

Please help <br>Much appreciated

mafiozo [28]

Answer:

x^2 -10x+25

Step-by-step explanation:

(x-5)^2

Rewriting

(x-5)(x-5)

FOIL

first: x*x = x^2

outer: x* -5 = -5x

inner: -5*x = -5x

last: -5 * -5 = +25

Add them together

x^2 -5x-5x+25

Combine

x^2 -10x+25

8 0

3 years ago

Read 2 more answers

PLZZZZZZ NEED HELP!!!!!!!

tatyana61 [14]

The answer is (4,-3.4)

3 0

3 years ago

What is the product?

Tanzania [10]

Answer:

$=\begin{pmatrix}-5&6\\ 1&-4\end{pmatrix}$

Step-by-step explanation:

$\begin{pmatrix}-3&4\\2&-5\end{pmatrix}\begin{pmatrix}3&-2\\ 1&0\end{pmatrix}$

Multiply the row of the first matrix to the column of the second matrix

$\begin{pmatrix}-3&4\end{pmatrix}\begin{pmatrix}3\\ 1\end{pmatrix}=\left(-3\right)\cdot \:3+4\cdot \:1$

$\begin{pmatrix}-3&4\end{pmatrix}\begin{pmatrix}-2\\ 0\end{pmatrix}=\left(-3\right)\left(-2\right)+4\cdot \:0$

$\begin{pmatrix}2&-5\end{pmatrix}\begin{pmatrix}3\\ 1\end{pmatrix}=2\cdot \:3+\left(-5\right)\cdot \:1\$

$\begin{pmatrix}2&-5\end{pmatrix}\begin{pmatrix}-2\\ 0\end{pmatrix}=2\left(-2\right)+\left(-5\right)\cdot \:0\$

$=\begin{pmatrix}\left(-3\right)\cdot \:3+4\cdot \:1&\left(-3\right)\left(-2\right)+4\cdot \:0\\ 2\cdot \:3+\left(-5\right)\cdot \:1&2\left(-2\right)+\left(-5\right)\cdot \:0\end{pmatrix}$

simplifying them we get

$=\begin{pmatrix}-5&6\\ 1&-4\end{pmatrix}$

8 0

3 years ago