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bonufazy [111]
3 years ago
8

Which inequality statement best represent the graph?

Mathematics
1 answer:
Vika [28.1K]3 years ago
4 0
The parabola is looking down, so it can be A. or D.
The colored area is inside the parabola, that means that values of y inside the parabola is less than values of y of the parabola.
So,
the answer is D. f(x)< -x²+x-1
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If you where born in 1620 and died in 1730 how old where u before u died?<br><br><br> pls help ;-;
Tema [17]

To make it simple, just subtract the age that you died to the age that you were born.

1730 - 1620 = 110

Which means that you would die at the age of 110 if you were born at 1620 and died on 1730.

5 0
3 years ago
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Work out the value of 3 to the power of minus 2 give your answer as a fraction
aivan3 [116]
Your answer is 3 because all you do is form it in a fraction
8 0
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PLEASE HELP I WILL BE PICKING BRAINLIEST
vagabundo [1.1K]

Answer:

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Step-by-step explanation:

3 0
3 years ago
I need to simplify √(5+2√2) and √(6+2√5)
SIZIF [17.4K]
This expression is easier than it looks like. I thought that to solve it you have for example to express the 2 via 10 * 5^-1 and stuff like that - but you can multiply and divide this expression by some factor. In our case first we multiply by conjunctive expression root(5-2root2) and the second by root(6+2root5). In first we get root16 and the second calculate.
6 0
2 years ago
Solve the inequality. Check your solutions.
Komok [63]
The inequality is 

7- \frac{2}{b}\ \textless \ \frac{5}{b}

write 7 as 7b/b to have all the expressions in common denominator:

\frac{7b}{b} - \frac{2}{b}\ \textless \ \frac{5}{b}

\frac{7b-2}{b} \ \textless \ \frac{5}{b}

\frac{7b-2}{b}- \frac{5}{b}\ \textless \ 0

\frac{7b-2-5}{b}\ \textless \ 0

\frac{7b-7}{b}\ \textless \ 0

\frac{7(b-1)}{b}\ \textless \ 0

here b=1 is a root and b=0 is not in the domain of the expression, but it still has an effect in the sign of the expression.

the sign table of \frac{7(b-1)}{b} is :

+++++++[0] --------[1] +++++

this means that for values of b to the left of 0 and to the right of 1, the expression is positive, and for values of b in (0, 1), the expression is negative.

that is \frac{7(b-1)}{b}\ \textless \ 0 for b∈(0, 1)

Answer: (0, 1)
8 0
3 years ago
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