Answer:
a and c would also be perpendicular
Step-by-step explanation:
because a║b and b⊥c you would use the transitive property of equality.
Notice the picture below
negative angles, are just angles that go "clockwise", namely, the same direction a clock hands move hmmm so.... and one revolution is just 2π
now, you can have angles bigger than 2π of course, by simply keep going around, so, if you go around 3 times on the circle, say "counter-clockwise", or from right-to-left, counter as a clock goes, 3 times or 3 revolutions will give you an angle of 6π, because 2π+2π+2π is 6π
now... say... you have this angle here... let us find another that lands on that same spot
by simply just add 2π to it :)

now, that's a positive one
and

to get more, just keep on subtracting or adding 2π
Hello here is a solution :
<span>x² − 8x − 4 = 0.
</span><span>quadratic equation ax²+bx+c = 0 when : a=1 and b= -8 and c = -4
discriminant : d = b²-4ac d= (-8)²-4(1)(-4) =64+16 =70
x= (-b-rot(d))/2a </span>x'= (-b+rot(d))/2a .......conrinu
That implies a simple multiplication, with a couple considerations:
17.5 percent = 17.5% = 17.5/100 = 175/1000
so we multiply both quantities:
17.5% of 2400
= (17.5%)(2400)
= (175/1000)<span>(2400)
</span>= 175*2400/1000
= 420
Answer:
Step-by-step explanation:
You correct