Question

What is the perimeter of rectangle JKLM?

Answer 1

Answer: Third option.

Step-by-step explanation:

The missing figure is attached.

The perimeter of a rectangle can be calculated with:

$P=2l+2w$

Where "l" is the length and "w" is the width.

We can see that the width of this rectangle is:

$w=12\ units$

So, we need to find the lenght.

Let be P the point  of intersection of the diagonals.

The diagonals of a rectangle are equal.

Since:

$JM=12\\MO=10$

We know that, by definition:

$JP=LP=MP=KP$

Then, we can find the lenght of the rectangle by using the Pythagorean Theorem:

$MK^2=KL^2+LM^2$

We can identify that:

$MK=10\ units+10\ units=20\ units\\KL=12\ units$

Then, subsituting values and solving for "LM", we get:

$20^2=LM^2+12^2\\\\LM=\sqrt{20^2-12^2}\\\\LM=16\ units$

Substituting values into the formula for calculate the perimeter, we get:

$P=2(16}\ units)+2(12\ units)=56\ units$

Answer 2

Answer:

C

Step-by-step explanation: