Answer:
5(-2w)-(5x4)
Step-by-step explanation:
Answer:
C
Step-by-step explanation:
calculate like terms, then it is pretty simple from there.
In a throw of 2 fair dice, there are 6*6=36 equiprobability outcomes.
To get a sum of 5, there are 4 ways, (1,4),(2,3),(3,2),(4,1) with probability of 4/36=1/9
To get at least one 5, there are 6+6-1=11 outcomes (note (5,5) has been counted in both, so subtracted from sum). The probability is 11/36
Since the two events are mutually exclusive (once we have a five, the sum can no longer be 5), we can add the probabilities to get the probability of one event or the other.
P(sum of 5 OR at least one 5)=1/9+11/36=4/36+11/36=15/36=5/9
Answer:
$43.95
Step-by-step explanation:
15/100 × 293
= 43.95
Answer:
1. 0.555555556
2. 18
Remember: Calculators exist lol.
