<u>G</u><u>iven </u><u>:</u><u>-</u>
- A right angled triangle with two sides 10cm and 9cm .
<u>To </u><u>Find</u><u> </u><u>:</u><u>-</u>
<u>Solution</u><u> </u><u>:</u><u>-</u>
At angle theta , 9cm side will be considered as the perpendicular and 10cm side will be hypotenuse . So , as we know that ;
Substituting the respective values,
Simplify,
Take arcsin both sides ,
<u>Hence</u><u> the</u><u> required</u><u> answer</u><u> is</u><u> </u><u>6</u><u>4</u><u>.</u><u>1</u><u>5</u><u>°</u><u> </u><u>.</u><u> </u>
Ok, so find circumference
arc/circumferece=xrad/2pirad
c=2pir
c=2pi6
c=12pi
arc=5.4cm
5.4/12pi=x/2pi
tims both sides by 2pi
5.4/6=x
0.9=x
0.9 radians
Answer:
11x + 5
Step-by-step explanation:
Answer:
Step-by-step explanation:
2x-10y=10
x=5
y=-1
5x+9y=-9
x= -9/5
y=-1
finding x and y intercept
<span>You can calculate the following probabilities:
1. Given that a sampled student is in the Spanish Club, what is the probability they got the Spanish class they requested?
2. Given that a sampled student is not in the Spanish Club, what is the probability they got the Spanish class they requested? If there is a significant difference between the two probabilities, it indicates there is a bias in the selection procedure.
</span><span>Given that, a sampled student is in the Spanish Club, the probability they got the Spanish class they requested is given by 265/335. Given that, a sampled student is not in the Spanish Club, the probability they got the Spanish class they requested is given by 100/165.
</span>
<span>If a student is at the Spanish club, the probability they got the Spanish class they requested is 265/335 = 0.79. If a student is not in the Spanish club, the probability they got the Spanish class they requested is 100/165 = 0.61.
</span>
<span>Based on the calculation, all students do not have an equal chance of getting into the Spanish class that they requested.</span>