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Zielflug [23.3K]
3 years ago
9

Find the midpoint P(16,7) and Q(12, -3) With work.

Mathematics
2 answers:
hichkok12 [17]3 years ago
8 0

Answer:

(14, 2 )

Step-by-step explanation:

Use the midpoint formula

[0.5(x₁ + x₂), 0.5(y₁ + y₂) ]

with (x₁, y₁ ) = (16, 7) and (x₂, y₂ ) = (12, - 3)

midpoint = [0.5(16 + 12), 0.5(7 - 3) ] = [0.5(28), 0.5(4) ] = (14, 2 )

valkas [14]3 years ago
6 0

Answer:

M= (14, 2)

Step-by-step explanation:

M= midpoint

M = ((x1+x2)/2), ((y1+y2)/2)

where:

x1=16

x2=12

y1=7

y2=-3

so we have:

M= ((16+12)/2) , ((7-3)/2)

M= (14, 2)

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Answer:

<u>For the first answer (A)</u>

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The volume of the prism is the base area multiplied by the height, or 28*10=280 cubic centimeters.

8 0
3 years ago
Read 2 more answers
A diameter of a circle has endpoints p(-10,-2) and Q(4,6)
kvasek [131]

Answer:

  a) center: (-3, 2)

  b) radius: √65

  c) equation: (x +3)² +(y -2)² = 65

Step-by-step explanation:

a) The center (point A) is the midpoint of the diameter, so its coordinates are the average of the endpoint coordinates:

  A = (P +Q)/2 = ((-10, -2) +(4, 6))/2

  = (-10+4, -2+6)/2 = (-6, 4)/2

  A = (-3, 2)

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b) The radius is the distance from the center to one end of the diameter. The distance formula can be used to find that.

  r = √((x2 -x1)² +(y2 -y1)²) = √((4-(-3))² +(6 -2)²) = √(49+16)

  r = √65

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c) The circle centered at (h, k) with radius r has formula ...

  (x -h)² +(y -k)² = r²

So the formula for this circle is ...

  (x +3)² +(y -2)² = 65

6 0
3 years ago
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Answer:

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Step-by-step explanation:

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jolli1 [7]

Answer:

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Step-by-step explanation:

The product of lengths to the near and far intersection points is the same for both secants:

  PB×PA = PD×PC

We can use this relation to solve for x, then use the value of x to find PD.

  7×12 = (3x)(7x)

  4 = x² . . . . . . . . . divide by 21

  2 = x . . . . . . . . . . take the square root

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  PD = 3x = 3·2

  PD = 6

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Answer:

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