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Anna11 [10]
2 years ago
9

11z 5 = 9z + 7 how do u solve this?

Mathematics
1 answer:
lorasvet [3.4K]2 years ago
6 0

Answer:Z=1


Step-by-step explanation: if it is 11z+5, then... minus 9z on each side to get 2z+5=7. Minus 5 on each side to get 2z=2. Divide bboth sides by two to get 1z=1.


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a. np and n(1-p) can be calculated as:

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#Both np and np(1-p) are greater than 5, hence, normal approximation is most appropriate:

\mu_x=11.04\\\\\sigma^2=np(1-p)=0.48\times 0.52\times 23=5.7408

#Define Y:

Y~(11.04,5.7408)

P(X\leq 12)\approx P(Y\leq 12.5)\\\\P(Z\leq \frac{(12.5-11.04)}{\sqrt{5.7408}})=\\\\=1-0.2709\\\\=0.7291

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b. The  probability that 5 or more fish were caught.

#Using normal approximation:

P(X \geq 5) \approx P(Y \geq 4.5) = P(Z \geq\frac{ (4.5-11.04)}{\sqrt{(5.7408)}})\\\\=1-0.0032\\\\=0.9968

Hence, the probability of catching 5+ is 0.9968

c. The probability of between 5 and 12 is calculated as;

-From b above P(X\geq 5)=0.9968 and a ,P(X\leq 12)=0.7291

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Hence, the probability of between 5 and 12 is 0.7259

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