Answer:
(3, 2), (6, 4)
Step-by-step explanation:
Since one end (A) of the segment AB is at the origin, the required points will be 1/3 and 2/3 of the coordinates of B:
(1/3)(9, 6) = (3, 2)
(2/3)(9, 6) = (6, 4)
a+b+c=0
[(a+b+c)^2=a^2+b^2+c^2+2ab+2ac+2bc]
[a^2+b^2+c^2+2ab+2ac+2bc=0]
[a^2+b^2+c^2=-(2ab+2ac+2bc)]
[a^2+b^2+c^2=-2(ab+ac+bc)] (i)
also
[a=-b-c]
[a^2=-ab-ac] (ii)
[-c=a+b]
[-bc=ab+b^2] (iii)
adding (ii) and (iii) ,we have
[a^2-bc=b^2-ac] (iv)
devide (i) by (iv)
[(a^2+b^2+c^2)/(a^2-bc)=(-2(ab+bc+ca))/(b^2-ac)]
Answer:
-3
Step-by-step explanation:
f(x)= x²+3x-1
f(-1)= (-1)²+3(-1)-1
= 1-3-1
= -2-1
= -3
