A (n + y) = 10y + 32
(an + ay) = 10y + 32
an + ay = 32 + 10y
Solve for "a"
-32 + an + ay + (-10y) = 32 + 10y + (-32) + (-10y)
-32 + an + ay + -10y = 32 + -32 + 10y + -10y
<span>- 32 + an + ay + (-10y) = 0 + 10y + (-10y)
- 32 + an + ay + (-10y) = 10y + (-10y)
</span><span>10y + -10y = 0
-32 + an + ay + (-10y) = 0
Thi could not be determined. (no solution)</span>
Hello from MrBillDoesMath!
Answer: 104x^2 + 166x + 66
Discussion:
The area of a rectangle is given by "length" * "width". For us the formula becomes
(13x + 11) * (8x+6)
or
13x (8x +6) + 11 * (8x + 6) =
(13x * 8x + 13x* 6) + ( 11*8x + 11*6) =
(104x^2 + 78x ) + (88x + 66) =
104x^2 + (78x + 88x) + 66 =
104x^2 + 166x + 66
Thank you,
MrB
The bisector of an angle of a triangle divides the opposite side into segments that are proportional to the adjacent sides
VT/TK = VY/YK
95.2/168 = 34/YK
YK = (168·34)/95.2 = 60 cm
x = VY + YK = 34 + 60 = 94 cm
x - 14 would be the equation
Does this help? Not really sure what you are asking.
