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3 years ago

Write as a polynomial (3p–1)(2p+5)–6p(p–2)

1 answer:

8 0

$\text{Simplify:}\\\\(3p-1)(2p+5)-6p(p-2)\\\\\text{Use FOIL:}\\\\6p^2+13p-5-6p(p-2)\\\\6p^2+13p-5-6p^2+12p\\\\\text{Combine like terms:}\\\\13p+12p-5\\\\\boxed{25p-5}$

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Find the missing factor 4n^2+9n+2=(4n+1)( ? ) <br> Please help me I don't know how to do this!

Bess [88]

The missing factor would be (n+2)... If you wanted to understand it, you simply solve 4n^2+9n+2 which gives you (4n+1)(n+2).

7 0

3 years ago

Which of the following is a solution to the equation y = 3x - 1 ?

Korvikt [17]

One way of determining the answer is by substituting the values to the equation. It is done as follows:

A. (4,1)
<span>y = 3x - 1
</span>1 = 3(4) - 1 = 11 -------> not equal

B. (2,5)
<span>y = 3x - 1
</span>5 = 3(2) - 1 = 5 --------> equal

C. (4,3)
<span>y = 3x - 1
</span>3 = 3(4) -1 --------------> not equal

D. (0, -3)
<span>y = 3x - 1
-3 = 3(0) -1 = -1 ---------> not equal</span>

8 0

3 years ago

X(x+5)>0<br><img src="https://tex.z-dn.net/?f=%20%7C2%20-%20%20%2B%20%20%2B%20%7C%20" id="TexFormula1" title=" |2 - + + | "

Aliun [14]

Answer:

here is the answer

FART.....

Step-by-step explanation:

7 0

3 years ago

Solve for x in the equation 3 x squared minus 18 x + 5 = 47.

Lana71 [14]

Answer:

first option

Step-by-step explanation:

3x² - 18x + 5 = 47 ( subtract 5 from both sides )

3x² - 18x = 42 ( divide through by 3 )

x² - 6x = 14

Using the method of completing the square

add ( half the coefficient of the x- term )² to both sides

x² + 2(- 3)x + 9 = 14 + 9

(x - 3)² = 23 ( take square root of both sides )

x - 3 = ± $\sqrt{23}$ ( add 3 to both sides )

x = 3 ± $\sqrt{23}$

6 0

3 years ago

HELP PLEASE ANYONE STEP BY STEP TIMED

UNO [17]

Answer:

$\huge\boxed{\text{B) 4}}$

Step-by-step explanation:

We can use the properties of some of these circles to solve and find the value of x.

FIrst off - we know that to find the side of a right triangle we can use the Pythagorean Theorem, which states that $a^2 + b^2 = c^2$ (a and b being legs, c being the hypotenuse.)

<h2><u>Finding the hypotenuse</u></h2>

We also know that this triangle is in a circle. Part of the hypotenuse and the altitude of the triangle are in the circle.

Point W is the center of the circle. Therefore, any points stretching to the edge from it will be equal (since this is a circle).

With this knowledge - UW and WZ are equal.

Therefore, since UW is $x-1$ , WZ will be too.

We also know the length of VZ. We can add this to WZ to find the length of the whole hypotenuse.

$\displaystyle x-1+2 \\ x+1$

So the length of the hypotenuse, WV, is $x+1$ .

<h2><u>Finding the value of x</u></h2>

Now that we know the length of the hypotenuse, we can use the Pythagorean Theorem like we stated before to find the value of x.

We know the two legs are $x-1$ and $2x-4$ , while the hypotenuse is

$\displaystyle (x-1)^2 + (2x-4)^2 = (x+1)^2$
$(x^2 - 2x + 1) + (4x^2-16x+16) = (x^2 + 2x + 1)$ (use FOIL to find the value of each expression squared)
$5x^2 - 18x + 17 = x^2 + 2x + 1$ (simplify the left side)
$4x^2 -20x + 16 = 0$ (subtract both sides by $x^2 +2x + 1$ )
$x = \frac{{ -b \pm \sqrt {b^2 - 4ac} }}{{2a}}$ (Quadratic formula)
$\frac{{ -(-20) \pm \sqrt {(-20)^2 - 4 \cdot 4 \cdot 16} }}{{2 \cdot 4}}$ (plug in values from equation)
$\frac{{ 20 \pm \sqrt {400 - 256} }}{8}}$ (simplify)
$\frac{{ 20 \pm \sqrt {144} }}{8}}$ (simplify)
$\frac{{ 20 \pm 12 }}{8}}$ (simplify)
$\displaystyle x = \frac{20+12}{8} \ \text{and} \ \frac{20-12}{8}$ (use plus/minus to find two roots)
$\displaystyle x = \frac{32}{8} \ \text{and} \ \frac{8}{8}$ (simplify)
$\displaystyle x = 4 \ \text{and} \ 1$

1 can not be a possible answer because UW would end up being $(1-1) = 0$ units long! This isn't possible!

Therefore, the correct answer would be B) 4.

Hope this helped!

6 0

3 years ago