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3 years ago

Write as a polynomial (3p–1)(2p+5)–6p(p–2)

1 answer:

8 0

$\text{Simplify:}\\\\(3p-1)(2p+5)-6p(p-2)\\\\\text{Use FOIL:}\\\\6p^2+13p-5-6p(p-2)\\\\6p^2+13p-5-6p^2+12p\\\\\text{Combine like terms:}\\\\13p+12p-5\\\\\boxed{25p-5}$

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En un paralelogramo de tiene ?

soldi70 [24.7K]

Answer:

Elementos y propiedades del paralelogramo

Lados: el paralelogramo tiene cuatro lados, siendo iguales y paralelos dos a dos (a y b). Ángulos: los ángulos interiores son iguales dos a dos, siendo iguales los ángulos no consecutivos (α y β). Como en todo cuadrilátero, sus ángulos interiores suman 360° (2α + 2β = 360°)

Step-by-step explanation:

Elements and properties of the parallelogram

Sides: the parallelogram has four sides, two by two (a and b) being equal and parallel. Angles: the interior angles are equal two by two, the non-consecutive angles (α and β) being equal. As in any quadrilateral, its interior angles add up to 360 ° (2α + 2β = 360 °) (English version lol)

6 0

3 years ago

The following data represent the monthly phone use, in minutes, of a customer enrolled in a fraud prevention program for the pas

Illusion [34]

Answer:

The answer is "717.25 minutes".

Step-by-step explanation:

In this question first, we arrange the value in ascending order that are:

307,311,321,322,354,363,377,406,425,435,461,464,474,499,505,513,517,534,548

The median is always in an orderly position that is $= \frac{(n+1)}{2}$ .

$\to \frac{(n+1)}{2} = \frac{(20+1)}{2} = 10.5$ position orders

$10^{th} \ and \ 11^{th}$ place an average of observations so, the

$Average = \frac{(425 +435)}{2} = \frac{(860)}{2} =430$

Because as medium stands at 10.5 that median is as below 10 are greater than the level.

$Q_1$ often falls throughout the ordered BELOW average is $= \frac{(n+1)}{2}$ place.

$\to \frac{(n+1)}{2} = \frac{(10+1)}{2} = 5.5^{th}$ ordered position

Average $5^{th} \ and \ 6^{th}$ location findings

$Q_1 = \frac{(354+363)}{2} = \frac{(717)}{2}= 358.5$

In $= \frac{(n+1)}{2}$ the ordered place, Q3 always falls ABOVE the median.

$\to \frac{(n+1)}{2} = \frac{(10+1)}{2} = 5.5^{th}$ ordered At median ABOVE

Consequently $Q_3$ falls between $5^{th} \ and \ 6^{th}$ ABOVE the median position

$15^{th}\ and \ 16^{th}$ place average of observations

$\to Q_3 = \frac{(499+505)}{2}=\frac{(1004)}{2} = 502$

$\to IQR = Q_3 - Q_1= 502-358.5= 143.5$

$\to \text{Upper fence} = Q_3 + 1.5 \times IQR= 502 + 1.5 \times 143.5 = 717.25$

4 0

3 years ago

Asapppppp!!!!!!!!!!!!!!!!!!!!!!!!!!!

svp [43]

Answer: x = 148 degrees

Step-by-step explanation:

This problem makes use of Supplementary Angles. Supplementary Angles states that two angles that make up a line add to 180. Thus, simply use the equation 32 + x = 180

x = 148

Hope it helps <3

5 0

3 years ago

Can somebody help me please

inna [77]

Answer:

104 degrees because 7 and 8 are congruent meaning 8 is also 104

Step-by-step explanation:

6 0

3 years ago

A ball is thrown into the air with an upward velocity of 24 ft/s. Its height h in feet after t seconds is given by the function

Natalija [7]

<span>D. 0.75 s; 16 ft is the best choice

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6 0

3 years ago

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