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tangare [24]
3 years ago
9

PLEASE HELPPPPPPPPPPPPPPOOP

Mathematics
2 answers:
Kitty [74]3 years ago
8 0

Answer:

72

Step-by-step explanation:

nikdorinn [45]3 years ago
8 0
The answer to this equation is 72
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What is the ratio of the area of the inner square to the area of the outer square?
Anastasy [175]

Answer:

\frac{(a-b)^2+b^2}{a^2}

Step-by-step explanation:

Since, By the given diagram,

The side of the inner square = Distance between the points (0,b) and (a-b,0)

=\sqrt{(a-b-0)^2+(0-b)^2}

=\sqrt{(a-b)^2+b^2}

Thus the area of the inner square = (side)²

=(\sqrt{(a-b)^2+b^2})^2

=(a-b)^2+b^2\text{ square cm}

Now, the side of the outer square = Distance between the points (0,0) and (a,0),

=\sqrt{(a-0)^2+0^2}

=\sqrt{a^2}=a

Thus, the area of the outer square = (side)²

=a^2\text{ square cm}

Hence, the ratio of the area of the inner square to the area of the outer square

=\frac{(a-b)^2+b^2}{a^2}

4 0
3 years ago
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Umnica [9.8K]

Answer:

I think the option B suits the most

Step-by-step explanation:

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3 years ago
WHAT VAULE MAKES THE TRIANGLE SIMILAR A.1.5 <br> B.5 c .6 d .9
alukav5142 [94]
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Please help! Late work!
frosja888 [35]
(40+41+41+45+48+48+49+49+49+40)/10 = 460/10 = 46

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Round your answers to one decimal place, if necessary.
Marina CMI [18]

Answer: 11

Step-by-step explanation:

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3 years ago
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