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Alona [7]
3 years ago
14

What is 6 3/4 as an improper fraction

Mathematics
2 answers:
Kobotan [32]3 years ago
8 0
<h3>♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷ Improper fractions are sometimes called 'top heavy fractions'

You'll see why below

Multiply 6 by 4:

6 x 4 = 24

Add 3 :

24 + 3 = 27

The improper fraction would be 27/4

<h3><u>✽</u></h3>

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

horsena [70]3 years ago
8 0
27 over 4 is the correct anwser
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PLEASE HELP ME!!! I NEED THIS REALLY SOON OR I WILL FAIL! What are some measurements that might be easier if we worked in the me
inessss [21]

Answer:

Centimeters might be easier because they can be much more precise than inches when there isn't an ideal length. Kilometers might be easier because it would not require such large numbers to work with.

Step-by-step explanation:

:)

5 0
4 years ago
A population of 100 frogs increases at an annual rate of 22%. How many frogs will there be in 5 years? Write an expression to re
gizmo_the_mogwai [7]
Exponential growth of the form:

F=Ar^t

F=100(1.22)^t

F(5)=100(1.22)^5

F(5)=270.27

F(5)=270 to the nearest frog...

....

1.22=r^12

r=1.22^(1/12)

F=100(1.22^(1/12)^t)

F=100(1.22^(t/12))  now it will produce monthly populations...

Say we did the same as before but instead of 5 years you have 60 months...

F(60)=100(1.22^(60/12))

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6 0
4 years ago
Help !!<br> Which transformation can not be used to prove that ABC is congruent to DEF ?
Over [174]

D

the answer is D. dilation cannot be used to prove this

4 0
3 years ago
Read 2 more answers
The function f(x)=(x-5)^2 +2 is not one-to-one. Identify a restricted domain that makes the function one-to-one, and find the in
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We have been given a quadratic function f(x)=(x-5)^{2} +2 and we need to restrict the domain such that it becomes a one to one function.

We know that vertex of this quadratic function occurs at (5,2).

Further, we know that range of this function is [2,\infty).

If we restrict the domain of this function to either (-\infty,5] or [5,\infty), it will become one to one function.

Let us know find its inverse.

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Upon interchanging x and y, we get:

x=(y-5)^{2}+2

Let us now solve this function for y.

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Hence, the inverse function would be f^{-1}(x)=5+\sqrt{x-2} if we restrict the domain of original function to [5,\infty) and the inverse function would be f^{-1}(x)=5-\sqrt{x-2} if we restrict the domain to (-\infty,5].

8 0
3 years ago
Find the solution of the system of equations 2x-4y=32 2x-8y=48
Sveta_85 [38]
<span>2x-4y=32
2x-8y=48
--------------subtract
4y = - 16
y  = -4

</span>2x-4y=32 
2x- 4(-4)=32 
2x + 16 = 32
2x = 16
x = 8

answer
(8, -4)
6 0
4 years ago
Read 2 more answers
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