Let
x ----------> the height of the whole poster
<span>y ----------> the </span>width<span> of the whole poster
</span>
We need
to minimize the area A=x*y
we know that
(x-4)*(y-2)=722
(y-2)=722/(x-4)
(y)=[722/(x-4)]+2
so
A(x)=x*y--------->A(x)=x*{[722/(x-4)]+2}
Need to minimize this function over x > 4
find the derivative------> A1 (x)
A1(x)=2*[8x²-8x-1428]/[(x-4)²]
for A1(x)=0
8x²-8x-1428=0
using a graph tool
gives x=13.87 in
(y)=[722/(x-4)]+2
y=[2x+714]/[x-4]-----> y=[2*13.87+714]/[13.87-4]-----> y=75.15 in
the answer is
<span>the dimensions of the poster will be
</span>the height of the whole poster is 13.87 in
the width of the whole poster is 75.15 in
All angles in a triangle add up to 180
So 79+37=116
180-116=64
Y=64
Hope this helps
Answer:
She need to walk 31/75 miles to school.
Step-by-step explanation:
It is given that,
Sofia has walk 
miles to school. She has already walk 
of a mile.
We need to find how much farther does she need to walk.
Total distance = 
Let she has to walk x distance to school.
Hence, she need to walk 31/75 miles to school.
The slope would be 4.33. He sells 13 cars in 3 months, 13/3=4.33 cars each month. While you can't sell 4.33, remember that this is just the slope. The equation would be apprx y=4.33(x)
