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3 years ago

|3 + y| - 4 = 7 solve

Mathematics

2 answers:

vfiekz [6]3 years ago

8 0

Answer:

y = 8 or y = -14

Step-by-step explanation:

Solve for y over the real numbers:

abs(y + 3) - 4 = 7

Add 4 to both sides:

abs(y + 3) = 11

Split the equation into two possible cases:

y + 3 = 11 or y + 3 = -11

Subtract 3 from both sides:

y = 8 or y + 3 = -11

Subtract 3 from both sides:

Answer: y = 8 or y = -14

natta225 [31]3 years ago

6 0

Answer:

y = 8 or y = -14

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Step-by-step explanation:

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3 years ago

The cost to rent an instrument is $65 for the first month it costs $30 for each additional month,x, that the instrument is rente

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3 years ago

Help me out now Please I'm stuck on this

Elena-2011 [213]

5x + 2(x + 1) ≤ 23

Distribute the 2.

5x + 2x + 2 ≤ 23

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3 years ago

Calculate the total area of the shaded region.

LUCKY_DIMON [66]

so hmmm seemingly the graphs meet at -2 and +2 and 0, let's check

$\stackrel{f(x)}{2x^3-x^2-5x}~~ = ~~\stackrel{g(x)}{-x^2+3x}\implies 2x^3-5x=3x\implies 2x^3-8x=0 \\\\\\ 2x(x^2-4)=0\implies x^2=4\implies x=\pm\sqrt{4}\implies x= \begin{cases} 0\\ \pm 2 \end{cases}$

so f(x) = g(x) at those points, so let's take the integral of the top - bottom functions for both intervals, namely f(x) - g(x) from -2 to 0 and g(x) - f(x) from 0 to +2.

$\stackrel{f(x)}{2x^3-x^2-5x}~~ - ~~[\stackrel{g(x)}{-x^2+3x}]\implies 2x^3-x^2-5x+x^2-3x \\\\\\ 2x^3-8x\implies 2(x^3-4x)\implies \displaystyle 2\int\limits_{-2}^{0} (x^3-4x)dx \implies 2\left[ \cfrac{x^4}{4}-2x^2 \right]_{-2}^{0}\implies \boxed{8} \\\\[-0.35em] ~\dotfill$

$\stackrel{g(x)}{-x^2+3x}~~ - ~~[\stackrel{f(x)}{2x^3-x^2-5x}]\implies -x^2+3x-2x^3+x^2+5x \\\\\\ -2x^3+8x\implies 2(-x^3+4x) \\\\\\ \displaystyle 2\int\limits_{0}^{2} (-x^3+4x)dx \implies 2\left[ -\cfrac{x^4}{4}+2x^2 \right]_{0}^{2}\implies \boxed{8} ~\hfill \boxed{\stackrel{\textit{total area}}{8~~ + ~~8~~ = ~~16}}$

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2 years ago

Which way shows how to make a ten to solve 13 - 7?

Paha777 [63]

13=10+3 so
13-7=3+10-7=3+3=6

3 0

3 years ago