Answer:
Step-by-step explanation:
Given that the probability that an American company will open a location in Shanghai, China is 0.7.
The probability that it will open a location in Beijing, China is 0.4.
The probability that it will open a location in either Shanghai or Beijing or both is 0.8.
the probability that the company will open a location in:
(a) both Shanghai and Beijing :

P(both) = 0.3
(using addition theory of probability for union of sets)
(b) neither Shanghai nor Beijing
= 1- P(AUB)

(c) Beijing but not in Shanghai?
P(Beiging)_P(both) = 
(d) Shanghai given that it opens a location in Beijing
=P(Both)/P(Beijing) = 
Think of the contents of the bag having 6 equal parts (in numerical quantity). Then the fraction of all the marbles which happen to be white marbles is 1/6. This converts to 16.67%.
8w-15= 17
17+15=32
32/8
W= 4
A.) 7^4x = 10
log base 10 (7^4X) = log base 10 (10)
4x log base 10 (7) = 1
4x (0.8451) = 1
3.3804x = 1
x = 0.2958
b.) ln(2) + ln(4x-1) = 5
ln (2 * 4x-1) = 5
ln (8x-2) = 5
log base (3) (8x-2) = 5
e^5 = 8x-2
e^5+2 = 8x
x = 18.8016