Answer:
Step-by-step explanation:
Compute the value of each expression.
Compare the values If they are equal the expressions are equivalent.
Answer:
Step-by-step explanation:
a.) the maximum is just the vertex
-35/(2*-4.9)= it takes 3.5714 seconds to hit the maximum
which in height is
-4.9*3.5714^2+35*3.5714 +1= 63.5 metres
b.) for this just plug in 2
-4.9*2^2+35*2+1= 51.4 metres
c.) just plug in f(0) =1 meter
d.) find the x intercepts (using the quadratic formula)
seconds
(there is another answer but it doesn't make sense in the context of this question)
Answer:x^(4/3)y^(16/3)
Step-by-step explanation:
X^(2×2/3)y^(8×2/3)=x^(4/3)y^(16/3)
Answer:
times 2
Step-by-step explanation:
2×2=4
-7×2=-14
which is why the scale factor is times 2
Answer:
1.) 8.09g ; 2) 206.7 years
Step-by-step explanation:
Given the following :
Half-life(t1/2) of Uranium-232 = 68.9 years
a) If you have a 100 gram sample, how much would be left after 250 years?
Initial quantity (No) = 100g
Time elapsed (t) = 250 years
Find the quantity of substance remaining (N(t))
Recall :
N(t) = No(0.5)^(t/t1/2)
N(250) = 100(0.5)^(250/68.9)
N(250) = 100(0.5)^3.6284470
N(250) = 100 × 0.0808590
= 8.0859045
= 8.09g
2) If you have a 100 gram sample, how long would it take for there to be 12.5 grams remaining?
Using the relation :
N / No = (1/2)^n
Where N = Amount of remaining or left
No = Original quantity
n = number of half-lifes
N = 12.5g ; No = 100g
12.5 / 100 = (1/2)^n
0.125 = (1/2)^n
Converting 0.125 to fraction
(1/8) = 1/2^n
8 = 2^n
2^3 = 2^n
n = 3
Recall ;
Number of half life's (n) = t / t1/2
t = time elapsed ; t1/2 = half life
3 = t / 68.9
t = 3 × 68.9
t = 206.7 years
