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3 years ago

What is 524.47 rounded to the nearest tenth?

Mathematics

2 answers:

Alexxandr [17]3 years ago

6 0

B. 524.5

hoped I helped :)

kolbaska11 [484]3 years ago

3 0

The tenth place is the first number to the right of a decimal. To determine if you're rounding or not, check the hundred's place, 2 numbers to the right of a decimal, for 5 or higher. If it's .45, round to .5, if it's .44, round to .4
Your answer is 524.5, which is B.)

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The waiting time at an elevator is uniformly distributed between 30 and 200 seconds. what is the probability a rider must wait m

stira [4]

1.5 minutes = 90 second

The probability density function is

$f_X(x)=\begin{cases}\dfrac1{200-30}=\dfrac1{170}&\text{for }30\le x\le200\\\\0&\text{otherwise}\end{cases}$

so the probability of interest is

$\mathbb P(X>90)=\displaystyle\int_{90}^\infty f_X(x)\,\mathrm dx$
$\mathbb P(X>90)=\dfrac1{170}\displaystyle\int_{90}^{200}\mathrm dx$
$\mathbb P(X>90)=\dfrac{200-90}{170}=\dfrac{11}{17}\approx0.6471$

5 0

3 years ago

The height (in meters) of a projectile shot vertically upward from a point 4 m above ground level with an initial velocity of 25

Assoli18 [71]

Answer:

(a) The velocity after 2 second is 5.9 m/s

The velocity after 4 second is -13.7 m/s.

(b) The projectile reaches its maximum height after 2.60 s of projection.

(c)The maximum height that is attained by the projectile is 37.18 m.

(d)Therefore the projectile hits the ground after 5.36 seconds of projection.

(e)The velocity of the projectile when it hits the ground is 27.03 m/s

Step-by-step explanation:

Given that, a projectile shot vertically upward from a point 4 m above the ground with a initial velocity of 25.5 m/s.

The height of the projectile after t seconds is

$h=4+25.5t-4.9t^2$

where h is in meter.

(a)

We use the formula

v=u+at

V= final velocity

u = initial velocity = 25.5 m/s

a = acceleration= acceleration due to gravity= 9.8 m/s²

Since the object moves upward direction and acceleration due to gravity is downward direction. So here a= -9.8 m/s.

v(2)= 25.5+(-9.8)×2

=25.5-19.6

=5.9 m/s

And when t= 4

v(4)= 25.5+(-9.8)×4

=25.5-39.2

= -13.7 m/s

The velocity after 2 second is 5.9 m/s

The velocity after 4 second is -13.7 m/s.

(b)

At its maximum height,the velocity of the projectile is zero. i.e v=0

∴0=25.5+(-9.8)t

⇒9.8t=25.5

$\Rightarrow t=\frac{25.5}{9.8}$

⇒t = 2.60 s

The projectile reaches its maximum height 2.60 s after projection.

(c)

To find the maximum height, we are putting t= 2.60 in this equation $h=4+25.5t-4.9t^2$ .

$\therefore h= 4+(25.5\times 2.60)-(4.9\times 2.60^2)$

=37.18 m

The maximum height that is attained by the projectile is 37.18 m.

(d)

When the projectile hits the ground the height will be zero i.e h=0

From the equation of height we get

$\therefore h=0=4+25.5t-4.9t^2$

$\Rightarrow 4+25.5t-4.9t^2=0$

$\Rightarrow t=\frac{-25.5\pm\sqrt{25.5^2-4(-4.9).4}}{2(-4.9)}$

⇒t= -0.15 ,5.36

Therefore it hits the ground after 5.36 seconds of projection.

(e)

To find the velocity we use the formula v=u+at

Here v = final velocity=?

u=25.5 m/s,

t = 5.36 s

a= -9.8m/s²

v=25.5+(-9.8)5.36

= -27.03 m/s

Negative sign denoted that the motion of the projectile is downward direction.

The velocity of the projectile when it hits the ground is 27.03 m/s.

6 0

2 years ago

write and solve a division problem that divides a 4 digit number by a 2 digit. how did you estimate the first digit of the quoti

Contact [7]

2 you should get this rite

8 0

3 years ago

I need some help plz???

GaryK [48]

I think the ones that would apply to this would be a. b. and c.

Since they are on the same line the slope doesn't change!

Hope I helped :)

6 0

3 years ago

Enter a decimal that equivalent to 6/100

choli [55]

Answer:

0.06

Step-by-step explanation:

5 0

2 years ago