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chubhunter [2.5K]
3 years ago
14

Write equations for the horizontal and vertical lines passing through the point (4, -5).

Mathematics
1 answer:
raketka [301]3 years ago
8 0

Answer:

Horizontal line: y=-5

Vertical line: x = 4

Step-by-step explanation:

As we have to determine the equations for the horizontal and vertical lines passing through the point (4, -5).

  • To determine the equation for the horizontal line passing through the point (4, -5), we must observe that the horizontal line will always have the same y-value regardless of the x-value.

Therefore, the equation of the horizontal line passing through the point (4, -5) will be: y=-5

  • To determine the equation for the vertical line passing through the point (4, -5), we must observe that the vertical line will always have the same x-value regardless of the y-value.

Therefore, the equation of the vertical line passing through the point (4, -5) will be: x=4

Hence:

Horizontal line: y=-5

Vertical line: x = 4

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What is the value of the expression 2/4^-3?
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What is a radius of a circle given by the equation x²-2x+8y-47=0
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Divide by 8.
y=-\frac{x^2}{8}+\frac{x}{4}+\frac{47}{8}
Factor out coefficient.
y=-\frac{1}{8}\left(x^2-2x\right)+\frac{47}{8}
Then, we are going to convert x into square form.
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Convert the whole expression into square form.
y=-\frac{1}{8}\left(x-1\right)^2+\frac{1}{8}\cdot \:1+\frac{47}{8}
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Subtract 6 from both sides.
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The radius of the circle will be -2. Also, no matter what the sign says, the radius has to always be positive. 
Have a nice day! :)
7 0
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