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3 years ago

6

Jazz draws a transversal, t, on two parallel lines AB and CD, as shown below:

1 answer:

Liula [17]3 years ago

7 0

I think it’s A. Hope this helped

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mr Goodwill [35]

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Step-by-step explanation:

-3+12=9

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Add the product of 2 and 5 to the product of 9 and 8

Lerok [7]

Answer:

82

Step-by-step explanation:

2*5 + 9*8 = 10 + 72 = 82

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Jane had of a meter of ribbon. She used of a meter of ribbon to decorate a card. How much ribbon did she have left after she dec

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2 years ago

I need to find the derivative. I’m not very good at this so I am answer asap would be sosososo helpful

Bingel [31]

Answer:

See below.

Step-by-step explanation:

First, notice that this is a composition of functions. For instance, let's let $f(x)=\sqrt{x}$ and $g(x)=7x^2+4x+1$ . Then, the given equation is essentially $f(g(x))=\sqrt{7x^2+4x+1}$ . Thus, we can use the chain rule.

Recall the chain rule: $\frac{d}{dx}[f(g(x))]=f'(g(x))\cdot g'(x)$ . So, let's find the derivative of each function:

$f(x)=\sqrt{x}=x^\frac{1}{2}$

We can use the Power Rule here:

$f'(x)=(x^\frac{1}{2})'=\frac{1}{2}(x^{-\frac{1}{2} })=\frac{1}{2\sqrt{x}}$

Now:

$g(x)=7x^2+4x+1$

Again, use the Power Rule and Sum Rule

$g'(x)=(7x^2+4x+1)'=(7x^2)'+(4x)'+(1)'=14x+4$

Now, we can put them together:

$y'=f'(g(x))\cdot g'(x)=\frac{1}{2\sqrt{g(x)}} \cdot (14x+4)$

$y'=\frac{14x+4}{2\sqrt{7x^2+4x+1} } =\frac{7x+2}{\sqrt{7x^2+4x+1} }$

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3 years ago