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3 years ago

Find the surface area of the cone to the nearest tenth.

Mathematics

2 answers:

vfiekz [6]3 years ago

7 0

Surface area = base area + side area

= pi * 7^2 + pi * 7 * 27 = 238pi = 747.7 cm^2

leonid [27]3 years ago

3 0

So i also need closure on this question actualy taking the geometry examen rn... and i figured i had to do (pi)* 7^2 = 152.938......
soooo like this is what you gone do....
(pi) * 7^2+ (pi) *7 *27
=747.6990.....
hope this helps
THE STRUGGLE IS REAL

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You pay $10 to play the following game of chance. there is a bag containing 12 balls: three are red, five are green, and the res

Bogdan [553]

Answer:

$ -2.08 expected to lose

Step-by-step explanation:

3 25.0% $15.00 $5.00 $1.25

5 41.7% $10.00 $- $-

4 33.3% $- $(10.00) $(3.33)

$(2.08) expected to lose

7 0

3 years ago

A car starts with a dull tank of gas. After driving around 5he city, 1/7 of the gas has been used. With the rest of the gas in t

Sati [7]

Answer:

$\frac{2}{7}$

Step-by-step explanation:

Given:

A car starts with a dull tank of gas

1/7 of the gas has been used around the city.

With the rest of the gas in the car, the car can travel to and from Ottawa three times.

Question asked:

What fractions of a tank of gas does each complete trip to Ottawa use?

Solution:

Fuel used around the city = $\frac{1}{7}$

Remaining fuel after driving around the city = 1 - $\frac{1}{7}$

= $\frac{7 - 1}{7} = \frac{6}{7}$

According to question:

As from the rest of the gas in the car that is $\frac{6}{7}$ , the car can complete 3 trip to Ottawa which means,

By unitary method:

The car can complete 3 trip by using = $\frac{6}{7}$ tank of gas.

The car can complete 1 trip by using = $\frac{6}{7} \div 3$

= $\frac{6}{7} \times\frac{1}{3}$

= $\frac{6}{21}$

= $\frac{2}{7}$ tank of gas

Thus, $\frac{2}{7}$ tank of gas used for each complete trip to Ottawa.

5 0

3 years ago

A typical sugar cube has an edge length of 1.00 cm. Imagine you have a cubical box that contains a mole of sugar cubes, perfectl

alisha [4.7K]

Answer:

844368.7 m

Step-by-step explanation:

We are given that a typical sugar cube has an edge length of 1.00 cm.

We have to find the edge length of the box in meters.

Edge length of sugar cube=1 cm = $10^{-2}m$ ( $1 cm=\frac{1}{100}m$ )

Volume of a sugar cube= $side\times side\time side=(10^{-2})^3=10^{-6}m^3$

1 mole of sugar= $6.02\times 10^{23}units$

Volume of 1 unit= $10^{-6} m^3$

Volume of $6.02\times 10^{23}$ units= $6.02\times10^{23}\times 10^{-6}=6.02\times 10^{17} m^3$

Volume of box=1 mole of sugar= $6.02\times 10^{17} m^3$

Edge length of box= $\sqrt[3]{6.02\times 10^{17}}=844368.7 m$

6 0

3 years ago

Elijah earned $476.00 at his job when he worked for 20 hours. What did he earn in one hour?

katovenus [111]

Answer:

23.80

You have to divide 476 by 20

3 0

3 years ago

Read 2 more answers

Please help me with this

timama [110]

Answer:

m<1 = 45°

m<2 = 76°

m<3 = 80°

Step-by-step explanation:

<u>Points to remember</u>

1). Vertically opposite angles are equal

2). Sum of angles of a triangles is 180°

<u>To find the measures of given angles</u>

From the figure we get,

m<1 = 45° [Vertically opposite angles]

By using angle sum property <2 + 59 + 45 = 180

m<2 = 180 - 104

m<2 = 76°

Also m<1 + m<3 + 55 = 180

m<3 = 180 - (m<1 + 55)

= 180 - (45 + 55)

= 180 - 100

m<3 = 80°

5 0

3 years ago