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3 years ago

16,051 round off to nearest thousand

1 answer:

7 0

16,000 is your answer :)
look next to the 6. Since it is less than 5, you do nothing to the 16 part and turn the rest to 0's.

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Jerry needs 216 posts to build a fence. He has 88 posts and needs P more. Write an equation that you could use to find the numbe

devlian [24]

Answer:

P = 128 Post

Step-by-step explanation:

Total post needed = 216 posts

Number of post Jerry has = 88 posts

Number of posts jerry still needs = P

Total = Number of post Jerry has + Number of posts jerry still needs

216 = 88 + P

216 - 88 = P

128 = P

P = 128 Post

7 0

3 years ago

Help a girl out please!

NeX [460]

Even function
(unchanged under reflection over y-axis)

Hope this helped :)

4 0

2 years ago

Brainliest and lots of points

Bas_tet [7]

Answer:

Step-by-step explanation:

I(x)=P(13x) = 2(13x)²+3(13x) +4

I(x)=P(13x).= 338x²+39x+4

6 0

3 years ago

Use dimensional analysis to convert the measurements.

jasenka [17]

Answer:

52.68 feet per hour

52.68 feet per 60 min

632.16 inches per 60 min

10.536 inches per minute

Step-by-step explanation:

3 0

3 years ago

To prove :One plus cot square theta into tan theta by sec square theta = cot theta

pickupchik [31]

we are given

$\frac{(1+cot^2(\theta))*tan(\theta)}{sec^2(\theta)} =cot(\theta)$

We will simplify left side and make it equal to right side

Left side:

$\frac{(1+cot^2(\theta))*tan(\theta)}{sec^2(\theta)}$

we can use trigonometric identity

$1+cot^2(\theta)=csc^2(\theta)$

we can replace it

$\frac{(csc^2(\theta))*tan(\theta)}{sec^2(\theta)}$

we know that

csc=1/sin and sec=1/cos

so, we can replace it

and we get

$\frac{cos^2(\theta)tan(\theta)}{sin^2(\theta)}$

now, we know that

tan =sin/cos

$\frac{cos^2(\theta)*sin(\theta)}{sin^2(\theta)*cos(\theta)}$

we can simplify it

and we get

$\frac{cos(\theta)}{sin(\theta)}$

we can also write it as

$=cot(\theta)$

Right Side:

$cot(\theta)$

we can see that

left side = right side

so,

$\frac{(1+cot^2(\theta))*tan(\theta)}{sec^2(\theta)} =cot(\theta)$ ......Answer

6 0

3 years ago