Answer:
5 ft
Step-by-step explanation:
If all sides are of the same length, we can multiply the value of one side by 3, because a triangle has three sides (and the perimeter is all sides added together), to find the perimeter.
× 3
can be rewritten as 
, so:
× 
The numerator & denominator share a common factor of 3, so:
5 ft is the final answer/perimeter.
hope this helps!
Answer:
Step-by-step explanation:
x
2
+
x
−
6
=
(
x
+
3
)
(
x
−
2
)
x
2
−
3
x
−
4
=
(
x
−
4
)
(
x
+
1
)
Each of the linear factors occurs precisely once, so the sign of the given rational expression will change at each of the points where one of the linear factors is zero. That is at:
x
=
−
3
,
−
1
,
2
,
4
Note that when
x
is large, the
x
2
terms will dominate the values of the numerator and denominator, making both positive.
Hence the sign of the value of the rational expression in each of the intervals
(
−
∞
,
−
3
)
,
(
−
3
,
−
1
)
,
(
−
1
,
2
)
,
(
2
,
4
)
and
(
4
,
∞
)
follows the pattern
+
−
+
−
+
. Hence the intervals
(
−
3
,
−
1
)
and
(
2
,
4
)
are both part of the solution set.
When
x
=
−
1
or
x
=
4
, the denominator is zero so the rational expression is undefined. Since the numerator is non-zero at those values, the function will have vertical asymptotes at those points (and not satisfy the inequality).
When
x
=
−
3
or
x
=
2
, the numerator is zero and the denominator is non-zero. So the function will be zero and satisfy the inequality at those points.
Hence the solution is:
x
∈
[
−
3
,
−
1
)
∪
[
2
,
4
)
graph{(x^2+x-6)/(x^2-3x-4) [-10, 10, -5, 5]}
There will be 130 nickels and 90 dimes. 100 nickels is 5 dollars. 90 dimes are 9 dollars. And then there will be 30 left. 30 dimes isn’t 1.50$ bur 30 nickels is 1.50$ so you add the 30 to the nickels and it’ll be exactly 15.50$.
Answer:
- So profit is denoted by Y
- Selling price is denoted by X
Hencd we have Y= X + B
Where Be can be a constant for example how much he already sold or etc.
Rate positively and give brainlist
412 ÷ 20 = 20 boxes with 12 remaining.
Total boxes needed = 20 + 1 = 21
Answer: 21 boxes will be needed.
