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3 years ago

Which is a perfect square?

Mathematics

2 answers:

ivann1987 [24]3 years ago

8 0

Answer:

121

Step-by-step explanation:

121= 11x11, that is the only option

140 has no square

168 is close, but still isn't a square

195 is 1 away from a square, but not a square

professor190 [17]3 years ago

6 0

Answer:

121

Step-by-step explanation:

THIS IS BECAUSE 11*11 = 121

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Find the value of the constant term in the expansion of x^4 (x+3/2x^2)^5

Nataly_w [17]

5 is the answer ok I'll explain

4 0

2 years ago

The length of ZX is 2 units. What is the perimeter of triangle XYZ?

dezoksy [38]

Keywords

triangle,perimeter,distance, length, side, points

we know that

The perimeter of a triangle is the sum of the three length side

To find the length side calculate the distance between two points

The formula to calculate the distance between to points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Step 1

Find the distance ZY

$Z(1,0)\\Y(3,1)$

substitute the values

$d=\sqrt{(1-0)^{2}+(3-1)^{2}}$

$dZY=\sqrt{5}\ units$

Step 2

Find the distance XY

$X(-1,4)\\Y(3,1)$

substitute the values

$d=\sqrt{(1-4)^{2}+(3+1)^{2}}$

$dXY=\sqrt{25}=5\ units$

Step 3

Find the perimeter of the triangle

$P=ZX+ZY+XY$

we have

$dZX=2\sqrt{5}\ units$

$dZY=\sqrt{5}\ units$

$dXY=5\ units$

Substitute

$P=(2\sqrt{5}+\sqrt{5}+5)\ units$

therefore

the answer is

$P=(3\sqrt{5}+5)\ units$

4 0

2 years ago

Read 2 more answers

Esterday 5% of the 120 sixth graders at school were late. How many sixth graders were late?

Vladimir [108]

Answer:6 six graders were late. 10% would be 12, and half of that is 6. You need to divide that in half because 5 is half of 10.

8 0

2 years ago

Read 2 more answers

The maximum value of 12 sin 0-9 sin²0 is: -

jeka57 [31]

Answer:

Step-by-step explanation:

The question is not clear. You have indicated the original function as 12sin(0) - 9sin²(0)

If so, the solution is trivial. At 0, sin(0) is 0 so the solution is 0

However, I will assume you meant the angle to be $\theta$ rather than 0 which makes sense and proceed accordingly

We can find the maximum or minimum of any function by finding the first derivate and setting it equal to 0

The original function is

$f(\theta) = 12sin(\theta) - 9 sin^2(\theta)$

Taking the first derivative of this with respect to $\theta$ and setting it equal to 0 lets us solve for the maximum (or minimum) value

The first derivative of $f(\theta)$ w.r.t $\theta$ is

$12\cos\left(\theta\right)-18\cos\left(\theta\right)\sin\left(\theta\right)$

And setting this = 0 gives

$12\cos\left(\theta\right)-18\cos\left(\theta\right)\sin\left(\theta\right) = 0$

Eliminating $cos(\theta)$ on both sides and solving for $sin(\theta)$ gives us

$sin(\theta) = \frac{12}{18} = \frac{2}{3}$

Plugging this value of $sin(\theta)$ into the original equation gives us

$12(\frac{2}{3}) - 9(\frac{4}{9} ) = 8 - 4 = 4$

This is the maximum value that the function can acquire. The attached graph shows this as correct

3 0

1 year ago

What is the equation of a line parallel to y=(3)/(4)x-5 and passes through (12,-2)?

Vika [28.1K]

A parallel line has the same slope as the original line. So in this case the slope of the line is also 3/4. Now how do we know if it intersects the point? We need to adjust the y intercept.

Currently, we know the equation of the line is y= 3/4 x + b, where b is the thing we are looking for. We also have a point, which supplies the x and y. Plug that in and solve for b

-2 = (3/4)*(12) + b

You'll get b= -11

So the equation of the parallel line intersecting the point given is y= 3/4x -11.

I am assuming that the slope is 3/4 based on the way you formatted the original equation, but it's the same steps if the slope is different.

3 0

1 year ago