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icang [17]
3 years ago
9

Which is a perfect square?

Mathematics
2 answers:
ivann1987 [24]3 years ago
8 0

Answer:

121

Step-by-step explanation:

121= 11x11, that is the only option

140 has no square

168 is close, but still isn't a square

195 is 1 away from a square, but not a square

professor190 [17]3 years ago
6 0

Answer:

121

Step-by-step explanation:

THIS IS BECAUSE 11*11 = 121

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A patio was to be laid in a design with one tile in the
Vlada [557]

Answer:

10

Step-by-step explanation:

The number of tiles in the design is 1 + 2 + 3 + ...

We can model this as an arithmetic series, where the first term is 1 and the common difference is 1.  The sum of the first n terms of an arithmetic series is:

S = n/2 (2a₁ + d (n − 1))

Given that a₁ = 1 and d = 1:

S = n/2 (2(1) + n − 1)

S = n/2 (n + 1)

Since S ≤ 60:

n/2 (n + 1) ≤ 60

n (n + 1) ≤ 120

n must be an integer, so from trial and error:

n ≤ 10

Mr. Tong should use 10 tiles in the final row to use the most tiles possible.

7 0
3 years ago
Determine if the two figures are congruent and explain your answer using transformations.
Vinil7 [7]

Answer: They are the same size

Step-by-step explanation:

Why they are the same size is because you can tell because of how it transforms, and by how the it looks and you flip it in reverse, and also of how it looks so yes, it is congruet. So I hope it helps you :)

3 0
2 years ago
Mrs. Evans gave her class a 100-page reading assignment. After 2 days, Kya and
Zarrin [17]

Answer:

so the answer is 20 because u know how she take it for days

4 0
2 years ago
The femur is the upper leg bone, and the tibia is one of the lower leg bones. the average length of the fumer is 50.5 cm,and the
Vilka [71]
50.5 cm + 43.03 cm = 93.53
7 0
2 years ago
Suppose that the proportions of blood phenotypes in a particular population are as follows: A B AB O 0.48 0.13 0.03 0.36 Assumin
Serggg [28]

Answer:

P(O and O) =0.1296

P=0.3778

Step-by-step explanation:

Given that

blood phenotypes in a particular population

A=0.48

B=0.13

AB=0.03

O=0.36

As we know that when A and B both are independent that

P(A and B)= P(A) X P(B)

The probability that both phenotypes O are in independent:

P(O and O)= P(O) X P(O)

P(O and O)= 0.36 X 0.36 =0.1296

P(O and O) =0.1296

The probability that the phenotypes of two randomly selected individuals match:

Here  four case are possible

So

P=P(A and A)+P(B and B)+P(AB and AB)+P(O and O)

P=0.48 x 0.48 + 0.13 x 0.13 + 0.03 x 0.03 + 0.36 x 0.36

P=0.3778

7 0
3 years ago
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