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prohojiy [21]
3 years ago
14

I need your help please​

Mathematics
1 answer:
Bess [88]3 years ago
4 0

56m^2

see the steps from the pic

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Please help me with homework
Ksivusya [100]

Answer:

1.) 5/4

2.) -4/5

3.) 1/4

4.) -1

5.) 1

Step-by-step explanation:

<u>Brainliest Please</u>

7 0
3 years ago
Multiply 6x4.2 I'm writing this to get it longer than 20 charictor s ​
Bingel [31]

Its 25.2 but what do u mean by that

7 0
2 years ago
Read 2 more answers
You have accepted a job offer at an annual salary of $36,980. This salary includes a year-end bonus of $2900. You are paid twice
Free_Kalibri [48]

Your gross pay will be $1595.2 for each paycheck

<h3>What are Arithmetic operations?</h3>

Arithmetic operations can also be specified by subtracting, dividing, and multiplying built-in functions. The operator that performs the arithmetic operation is called the arithmetic operator.

- Subtraction operation: Subtracts the right-hand operand from the left-hand operand.

for example 12 -2 = 10

* Multiplication operation: Multiplies values on either side of the operator

For example 12*2 = 24

You have accepted a job offer at an annual salary of $36,980.

This salary includes a year-end bonus of $2900

So your gross pay = 36980 + 2900 = 15952

You are paid twice per month

12 months × 2 checks = 24 paychecks

15952/ 25= 1595.2

Hence, your gross pay will be $1595.2 for each paycheck

Learn more about Arithmetic operations here:

brainly.com/question/25834626

#SPJ1

8 0
1 year ago
Solve the inequality.<br> 6+x&gt;56+x&gt;5
weqwewe [10]

Answer:

X>50

X>-51

Step-by-step explanation:

6+x>56

56+x>5

separate the equation into different equations by the sign

I) 6+x>56

x>56-6

x>50

ii) 56+x>5

x>5-56

x>-51

4 0
2 years ago
Assume the random variable X has a binomial distribution with the given probability of obtaining a success. Find the following p
Lisa [10]

Answer:

0.0064

0.00032

Step-by-step explanation:

Given the details:

P(X > 3), n = 5, p = 0.2

The binomial distribution is related using the formula:

P(x = x) = nCx * p^x * q^(n-x)

q = 1 - p = 1 - 0.2 = 0.8

P(X > 3) = p(x = 4) + p(x = 5)

P(x = 4) = 5C4 * 0.2^4 * 0.8^1 = 5 * 0.2^4 * 0.8^1 = 0.0064

P(x = 5) = 5C5 * 0.2^5 * 0.8^0 = 1 * 0.2^5 * 0.8^0 = 0.00032

3 0
2 years ago
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