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Yakvenalex [24]
3 years ago
10

Which are the solutions of x2 = –13x – 4?

Mathematics
1 answer:
AnnyKZ [126]3 years ago
5 0

x=(13±3√17)/2x

≈ 12.68465843, 0.31534156

Which would be 12.7 and 0.3 If you rounded to the nearest tenth.

You might be interested in
(1 point) Suppose we want a 95% confidence interval for the average amount spent on books by freshmen in their first year at col
Ne4ueva [31]

Answer:

a) n=(\frac{1.960(16)}{5})^2 =39.33 \approx 40

So the answer for this case would be n=40 rounded up to the nearest integer

b) For this case if we see the formula for the margin of error

ME=z_{\alpha/2}\frac{s}{\sqrt{n}}    (a)

We can see that the margin of error is inversely proportional to the sample size so if we want a samller margin of error we need a LARGER sample

Answer: LARGER

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean

\sigma=16 represent the population standard deviation

n represent the sample size  

Solution to the problem

Part a

The margin of error is given by this formula:

ME=z_{\alpha/2}\frac{s}{\sqrt{n}}    (a)

And on this case we have that ME =5 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2   (b)

The critical value for 95% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.025;0;1)", and we got z_{\alpha/2}=1.960, replacing into formula (b) we got:

n=(\frac{1.960(16)}{5})^2 =39.33 \approx 40

So the answer for this case would be n=40 rounded up to the nearest integer

Part b

For this case if we see the formula for the margin of error

ME=z_{\alpha/2}\frac{s}{\sqrt{n}}    (a)

We can see that the margin of error is inversely proportional to the sample size so if we want a samller margin of error we need a LARGER sample

Answer: LARGER

5 0
3 years ago
Answer please thanks for answer ​
zavuch27 [327]

Answer: 15.8

In this number, .8 is the tenths place. So round it to this number.

.839 rounded to nearest tenth = .8

Your result should be 15.8.

15.839 rounded to the nearest tenth is 15.8.

8 0
2 years ago
Giving brainliest!!!!!!!!!!
crimeas [40]
It’s C. hope this helped and good luck !!
5 0
2 years ago
Read 2 more answers
Help plz need this done
Marat540 [252]

Answer:

\cos(o)  =  \frac{12}{13}

Step-by-step explanation:

cos O = adjacent / hypotenuse

cos O = 12/13

I hope I helped you^_^

4 0
2 years ago
Read 2 more answers
70 POINTS SHOW WORK
lord [1]
Area of triangle = 1/2 x base x height

so old triangle we have  1/2 x b x h = 48

new triangle has base 3 times as long and height is half as long
 so we would get:

1/2 x (3B) x (1/2H) = area

rewrite as 1/2 x 3/2 x b x H = area

divide by original are os 1/2 x b x h and you end up with 3/2

so new area = 3/2 x old area

new area = 3/2 * 48 = 72 square inches
8 0
3 years ago
Read 2 more answers
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