Question

If h(x) = 5 x and k(x)=1/x, which expression is equivalent to (koh)(x)?

Answer 1

$(k\circ h)(x)=k(h(x))$

$\displaystyle k(h(x))= \frac{1}{h(x)}= \frac{1}{5x}$

Answer 2

For those who may still need it in the future, the correct answer is actually: B