You can see that angle TQV = 90 degrees
Angle RQV = 136 degrees
Angles RQV and UQV are supplementary and equal 180 degrees since they form a straight line. Therefore angle UQV = 180 - 136 = 44 degrees.
TQU + UQV = 90 degrees. Therefore, TQU = 90 - UQV.
90 - 44 = 46 degrees for angle TQU.
Answer:
x = 9.47 degrees ( in first quadrant.
Step-by-step explanation:
sin2x + sinx cos x = 1/2
Now sinx cos x = 1/2sin2x so:
3/2sin2x = 1/2
sin2x = 1/2 / 3/2
sin2x = 1/2 * 2/3 = 1/3
2x = arcsin 1/3 = 19.47 degrees
x = 9.74 degrees to nearest hundredth.
Consider this option:
C³₂₇=27!/(3!*24!)=25*13*9=2925 ways to select 3 students.
Answer:
G o o g l e >:>
Step-by-step explanation:
Answer:
40 degrees
Step-by-step explanation:
The 100 degree angle is supplementary to angle CED. This means CED will end up being 80 degrees. Since the angles in all triangles equate to 180 degrees 80 + 60 + angle D must equal 180 degrees. Therefore, angle D has to be 40 degrees.
