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Montano1993 [528]
3 years ago
10

Given 2x² = -8, x is

Mathematics
2 answers:
zubka84 [21]3 years ago
8 0
You would first divide by 2 which would get you x ^2= -4
then you have a negative so you’ll have two answers
your answers would be x=2 and x=-2
Sergeeva-Olga [200]3 years ago
7 0

Answer:

x = -2  x = 2  (irrational numbers)

Step-by-step explanation:

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Class a has x students and class b has y students. the average of class a is 85 and class b is 90. when the scores of class a an
Usimov [2.4K]
The total scores of the x students from class A can be calculated by multiplying x and the average which is equal to 85. That is 85x.

In similar manner, we are able to find for the total scores of the students from Class B. That would be, 90y.

Combining the scores, the new average then becomes 88. This is equal to,

                                 (85x + 90y) / (x + y ) = 88

Cross-multiplying,
                            85x + 90y = 88x + 88y

Combine all the x's and y's in each side of the equation.

                        85x - 88x = 88y - 90y

Combining terms,
                              -3x = -2y

The ratio is obtained through the step below,
                         -3x/-3y = -2y/-3y

                            x/y = 2/3

Thus, the ratio is 2/3. 
5 0
4 years ago
Simplify the expression. 4 + 5\3^2 - 2^2 <br> A) -3 <br> B) -5 <br> C) 5 <br> D) 9\5
DedPeter [7]

Answer:

D

Step-by-step explanation:

\frac{4+5}{3^{2}-2^{2}}=\frac{9}{9-4}\\\\=\frac{9}{5}

4 0
3 years ago
Write the set {x|x is a nonnegative real number} as an interval using interval notation.  
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Step-by-step explanation:

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3 years ago
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3 years ago
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If DM = 35, what is the value of r?
Gennadij [26K]

Answer:

r = 11

Step-by-step explanation:

Given

DM = 35

DG = r + 5

GM = 3r - 14

Required

Find r

From the question, we understand that G is a point between D and M:

This implies that:

DM = DG + GM

Substitute values for DM, DG and GM

35 = r + 5 + 3r - 14

Collect Like Terms

r + 3r = 35 - 5 + 14

4r = 44

Solve for r

r = 44/4

r = 11

3 0
4 years ago
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