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Andreas93 [3]
3 years ago
5

Help me solve this problem please

Mathematics
2 answers:
jeka57 [31]3 years ago
8 0

Answer:

x = -10

Explanation:

15 - 2 ( x + 5 ) = 25

Distribute 2 through the parentheses

15 - 2x - 10 = 25

Subtract the numbers

5 - 2x = 25

Move constant to the right-hand side and change its sign

-2x = 25 - 5

Subtract the numbers

-2x = 20

Subtract both sides

x = -10

BabaBlast [244]3 years ago
3 0

Answer:

x=-10

Step-by-step explanation:

15-2(x+5)=25

multiply the 2 by the x and 5 and you get

15-2x-10=25

since the 15 and the negative 10 are on the same side you add them together and get

5 -2x= 25

-5       -5

-2x =20

Then divide the -2/20= -10

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Andrew is thinking of a number less than 52 and greater than 40. his number has three ones. what is Andrew's number?
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Devi has a grid in the shape of a parallelogram. She has equilateral triangles. Each equilateral triangle has an area of 40 squa
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5 0
3 years ago
Place the indicated product in the proper location on the grid.
marishachu [46]

Answer:

See explanation

Step-by-step explanation:

1.

(a+b)(a^2-ab+b^2)=a^3-a^2b+ab^2+a^2b-ab^2+b^3=a^3+b^3

2.

(1-7x)(1+9x)=1+9x-7x-63x^2=-63x^2+2x+1

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(x+y+3)(x+y-4)=x^2+xy-4x+xy+y^2-4y+3x+3y-12=x^2+2xy+y^2-x-y-12

4.

(a-b)(a^2+ab+b^2)=a^3+a^2b+ab^2-a^2b-ab^2-b^3=a^3-b^3

5.

(m^3n+8)(m^3n-5)=(m^3n)^2-5m^3n+8m^3n-40=m^6n^2+3m^3n-40

6.

(4-(3c-1))(6-(3c-1))=(4-3c+1)(6-3c+1)=(5-3c)(7-3c)=35-15c-21c+9c^2=9c^2-36c+35

7.

(ab-9)(ab+8)=(ab)^2+8ab-9ab-72=a^2b^2-ab-72

8.

(a+b-c)(a+b+c)=a^2+ab+ac+ab+b^2+bc-ac-bc-c^2=a^2+b^2-c^2+2ab

9.

(a+3)(a-2)=a^2-2a+3a-6=a^2+a-6

10.

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11.

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12.

(x^2+2x-1)(x^2+2x+5)=x^4+2x^3+5x^2+2x^3+4x^2+10x-x^2-2x-5=x^4+4x^3+8x^2+8x-5

13.

(4x-3y+5)(x+2y-3)=4x^2+8xy-12x-3xy-6y^2+9y+5x+10y-15=4x^2+5xy-6y^2-7x+19y-15

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3 years ago
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Vaselesa [24]

Answer:

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Step-by-step explanation:

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