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bogdanovich [222]
3 years ago
13

If mZEFH = (5x + 1)', mZHFG = 62°, and mZEFG = (18x + 11)', find each measure.

Mathematics
1 answer:
Juli2301 [7.4K]3 years ago
6 0

Step-by-step explanation:

Given

mZEFH = (5x + 1)'

mZHFG = 62°

mZEFG = (18x + 11)',

The addition property of the angle is true

mZEFG = mZEFH + mZHFG

(18x + 11) = (5x + 1)'+  62

18x+11 = 5x + 63

collect like terms

18x - 5x = 63-11

13x = 52

divide both sides by 13

13x/13 = 52/13

x = 4

Since angle mZEFH = (5x + 1)' and x = 4, we will substitute x = 4 into the function;

mZEFH = 5(4) + 1

mZEFH = 20 + 1

mZEFH = 21°

Similarly for mZEFG = (18x + 11)'

mZEFG = 18(4) + 11

mZEFG =72+11

mZEFG = 83°

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add 12 to both sides and subtract 4x from both sides:

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3 0
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You blow a bubble in the shape of a sphere. It has a radius of 5 inches. Which choice is closest to its surface area?
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FUNDRAISING A school is raising money by selling calendars for $20 each. Mrs. Hawkins promised a party to whichever of her Engli
____ [38]

Rj, this is the solution to question 19:

• 1st period class sold 60 calendars in total

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• 2nd period class sold 123 calendars in total

We calculate the average per week, this way:

• 1st period class sold 60/4 = 15 calendars per week

,

• 2nd period class sold 123/4 = 30.75 calendars per week

In consequence the multiplication equation that represents this situation is:

15w + 30.75w = 183, where w is the number of weeks Mrs. Hawkins' classes sold calendars.

This is the solution to question 20:

We already know the average number of calendars that 1st and 2nd period classes sold per week. Now, let's calculate the average for 3nd 4th peiod classes, this way:

• 3rd period class sold 89 calendars in total

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• 4th period class sold 126 calendars in total

Therefore, the average is:

• 3rd period class sold 89/4 = 22.25 calendars per week

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• 4th period class sold 126/4 = 31.5 calendars per week

Summarizing, we have:

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7 0
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