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AURORKA [14]
3 years ago
13

Simplify m+{n-[p+q-(m-n+p-q)]}​

Mathematics
1 answer:
Serga [27]3 years ago
6 0

Answer:

m+n-p-q+m-n+p-q = 2m-2q

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What is 15% of 140
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URGENT! WILL GIVE BRAINLIEST!!
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Answer:

Option C) a_{n}=m-b+m(n-1) for n={\{1,2,3,...}\} is not the correct way to define the given infinite sequence

{\{m+b,2m+b,3m+b,4m+b,...}\}

Step-by-step explanation:

Given infinite sequence is {\{m+b,2m+b,3m+b,4m+b,...}\}

Option B) a_{n}=m-b+m(n-1) for n={\{1,2,3,...}\} is not the correct way to define the given infinite sequence {\{m+b,2m+b,3m+b,4m+b,...}\}

Now verify  a_{n}=m-b+m(n-1) for n={\{1,2,3,...}\} is true for the given infinite sequence

That is put n=1,2,3,.. in the above function

a_{n}=m-b+m(n-1)

When n=1,  a_{1}=m-b+m(1-1)

=m-b+0

a_{1}=m-b\neq m+b

When n=2,  a_{2}=m-b+m(2-1)

=m-b+m

a_{2}=2m-b\neq 2m+b

When n=3,  a_{3}=m-b+m(3-1)

=m-b+2m

a_{3}=3m-b\neq 3m+b

and so on.

Therfore a_{n}=m-b+m(n-1) for n={\{1,2,3,...}\} is not the correct way to define the given infinite sequence

{\{m+b,2m+b,3m+b,4m+b,...}\}

Therefore option C) is correct

5 0
3 years ago
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