All categories

3 years ago

When is g(x) = 0 for the function g(x) = 5.2 3x + 4?

1 answer:

6 0

G(x) = 0 can never happen.

When x is 0, the answer is 4
When x is 1, the answer is 19.6
When x is 4, the answer is 66.4

According to Wolfram Alpha though, x is equal to -(10/39). If that's not a choice for you, don't worry about it. :)

You might be interested in

A steel factory manufactures and sells steel beams

tankabanditka [31]

Answer:

That is very nice. I like steel factory's that manufacture and sell steel beams, they are my favorite!! :]

The question is bland...

And honestly what even is the question?

Step-by-step explanation:

I'll help but explain the question further

4 0

2 years ago

For a field trip 20 students rode in cars and the rest filled 5 busses. How many students were in each bus if 210 students were

xeze [42]

First do 210 - 20 = 190
Then do 190/5 = 38
38 people per bus is the answer!!!!

3 0

3 years ago

Read 2 more answers

Tell whether the triangle with the given side lengths is a right triangle.

Lerok [7]

Answer:

Step-by-step explanation:

6 0

3 years ago

Susie has $2 in coins in her purse. She has 3 times as many quarters as nickels. She has twice as many dimes as nickels. How man

zysi [14]

Answer:

120 coins our in her purse if the 2 dollar factor is made up of nickels

8 0

3 years ago

Factorise 2x^2 - 3x -2 < 0

Galina-37 [17]

Step 1: Factor $2 x^{2} - 3x -2$
1. Multiply 2 by -2, which is -4.
2. Ask: Which two numbers add up to -3 and multiply to -4?
3. Answer: 1 and -4
4. Rewrite $-3x$ as the sum of $x$ and $-4x$

$2 x^{2} +x-4x-2\ \textless \ 0$

Step 2: Factor out common terms in the first two terms, then in the last two terms.

 $x(2x+1)-2(2x+1)\ \textless \ 0$

Step 3: Factor out the common term $2x+1$

$(2x+1)(x-2)\ \textless \ 0$

Step 4: Solve for $x$

1. Ask: When will $(2x+1)(x-2)$ equal zero?
2. Answer: When $2x + 1 = 0$ or $x-2=0$
3. Solve each of the 2 equations above:

 $x=- \frac{1}{2} ,2$

Step 5: From the values of $x$ above, we have these 3 intervals to test.
x = < -1/2
-1/2 < x < 2
x > 2

Step 6: Pick a test point for each interval

For the interval $x\ \textless \ - \frac{1}{2} 
$
Lets pick $x=-1.$ Then, $2(-1) ^{2} -3 * -1 -2 \ \textless \ 0$
After simplifying, we get $3\ \textless \ 0$ , Which is false.
Drop this interval.

For this interval $- \frac{1}{2} \ \textless \ x\ \textless \ 2$
Lets pick $x=0$ . Then, $2* 0^{2} - 3 * 0-2\ \textless \ 0$ . After simplifying, we get $-2\ \textless \ 0,$ which is true. Keep this interval.

For the interval $x\ \textgreater \ 2$

Lets pick $x = 3.$ Then, $2 * 3 ^{2} -3*3-2\ \textless \ 0.$ After simplifying, we get $7\ \textless \ 0$ , Which is false. Drop this interval.

.Step 7: Therefore,
$- \frac{1}{2} \ \textless \ x\ \textless \ 2$

Done! :)

4 0

4 years ago