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Anna11 [10]
3 years ago
14

Please do a and b and explain

Mathematics
1 answer:
Blizzard [7]3 years ago
4 0

This is a decay problem,

The equation is written as start value x (1 - rate)^tike

Using the information given in the problem:

a) Total = 120(1-0.12)^Hours

b) Replace hours with 19 and solve:

Total = 120(1-0.12)^19

Total = 120(0.88)^19

Total = 10.57674 mg

Round the answer as needed.

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Ms speakman's smartphone is on sale for 25% off its list price. The sale priceof the smartphone is 51799,99, What expression can
Ber [7]

The expression that can be used to represent the list price of the smartphone is 5179.99 * (1- 25%) and the value is 3884.9925

<h3>What expression can be used to represent the list price of the smartphone? </h3>

The given parameters are:

Discount = 25%

Sales price = 5179.99

The expression that can be used to represent the list price of the smartphone is

Expression = Sales price * (1- discount)

So, we have:

Expression = 5179.99 * (1- 25%)

Evaluate

Expression = 3884.9925

Hence, the expression that can be used to represent the list price of the smartphone is 5179.99 * (1- 25%) and the value is 3884.9925

Read more about discounts at:

brainly.com/question/7459025

#SPJ1

3 0
1 year ago
HELP!! Two mechanics worked on a car. The first mechanic worked for 20 hours, and the second mechanic worked for 5 hours. Togeth
joja [24]

Answer:

  • first mechanic: $105/hour
  • second mechanic: $55/hour

Step-by-step explanation:

Let r represent the rate charged by the first mechanic. Then 160-r is the rate charged by the second mechanic. The total of charges is ...

  20r +5(160-r) = 2375

  15r +800 = 2375 . . . . . . eliminate parentheses

  15r = 1575 . . . . . . . . . . . . subtract 800

  r = 105 . . . . . . . . . . . . . . . divide by 15. First mechanic's rate.

  160-r = 55 . . . . . Second mechanic's rate

The first mechanic charged $105 per hour; the second, $55 per hour.

7 0
3 years ago
Read 2 more answers
Can someone help me with these 4 geometry questions? Pls it’s urgent, So ASAP!!!!
blagie [28]

<u>Question 4</u>

1) \overline{BD} bisects \angle ABC, \overline{EF} \perp \overline{AB}, and \overline{EG} \perp \overline{BC} (given)

2) \angle FBE \cong \angle GBE (an angle bisector splits an angle into two congruent parts)

3) \angle BFE and \angle BGE are right angles (perpendicular lines form right angles)

4) \triangle BFE and \triangle BGE are right triangles (a triangle with a right angle is a right triangle)

5) \overline{BE} \cong \overline{BE} (reflexive property)

6) \triangle BFE \cong \triangle BGE (HA)

<u>Question 5</u>

1) \angle AXO and \angle BYO are right angles, \angle A \cong \angle B, O is the midpoint of \overline{AB} (given)

2) \triangle AXO and \triangle BYO are right triangles (a triangle with a right angle is a right triangle)

3) \overline{AO} \cong \overline{OB} (a midpoint splits a segment into two congruent parts)

4) \triangle AXO \cong \triangle BYO (HA)

5) \overline{OX} \cong  \overline{OY} (CPCTC)

<u>Question 6</u>

1) \angle B and \angle D are right angles, \overline{AC} bisects \angle BAD (given)

2) \overline{AC} \cong \overline{AC} (reflexive property)

3) \angle BAC \cong \angle CAD (an angle bisector splits an angle into two congruent parts)

4) \triangle BAC and \triangle CAD are right triangles (a triangle with a right angle is a right triangle)

5) \triangle BAC \cong \triangle DCA (HA)

6) \angle BCA \cong \angle DCA (CPCTC)

7) \overline{CA} bisects \angle ACD (if a segment splits an angle into two congruent parts, it is an angle bisector)

<u>Question 7</u>

1) \angle B and \angle C are right angles, \angle 4 \cong \angle 1 (given)

2) \triangle BAD and \triangle CAD are right triangles (definition of a right triangle)

3) \angle 1 \cong \angle 3 (vertical angles are congruent)

4) \angle 4 \cong \angle 3 (transitive property of congruence)

5) \overline{AD} \cong \overline{AD} (reflexive property)

6) \therefore \triangle BAD \cong \triangle CAD (HA theorem)

7) \angle BDA \cong \angle CDA (CPCTC)

8) \therefore \vec{DA} bisects \angle BDC (definition of bisector of an angle)

8 0
2 years ago
A can of paint is 11 inches high and Has a diameter of 8 inches. what is the volume of the can in cubic inches?
tensa zangetsu [6.8K]
4^2 = 16

16 x 11 x 3.14 = 

V ≈ 552.92
8 0
3 years ago
2. Define any variables and tell the slope and y-intercept of the situation. Then, write an equation to represent
Otrada [13]

Answer:

x=number of hours

c(x)= 25x+75

y-intercept= (0, 75)

Equation= y=25x+75

Slope= 25

Step-by-step explanation:

75 would be the y intercept(constant) because that's the initial charge for a call.

25 would be the coefficient for x because the hour you spend on the call varies.

The slope is how steep the line is, in this case it is 25.

x is the number of hours because that is the time that varies.

3 0
3 years ago
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