Hip Breadths and Aircraft Seats
Engineers want to design seats in commercial aircraft so that they are wide enough to fit 98% of all males. (Accommodating 100% of males would be too expensive.) Men have hip breadths that are normally distributed with a mean of 14.4 in. and a standard deviation of 1.0 in. Find P 98. That is, find the hip breadth for men that separates the smallest 98% from the largest 2%.
Answer:
B = (C-Ax)/y
Step-by-step explanation:
Solve for B.
Ax+By=C
making B the subject of formula '
Ax+By=C
subtract Ax from both sides
By = C-Ax
By = C-Ax
divide both sides by y
B = (C-Ax)/y
If <span>(5^2-4) / (5+2) then
=(25 - 4 )/3
= 21/3
= 7
if 4/5 fraction then
</span><span>5^2-4/5+2
= 25 - 4/5 + 2
= 27 - 4/5
= 26 5/5 - 4/5
= 26 1/5
= 26.2</span>
Answer:
<u>27 x 2 </u> = <u>54 </u> = 54% 54% of racers finished in less than 57 minutes
50 x 2 = 100 =
Answer:
184
Step-by-step explanation:
in the number 128 the number eight is right it should be to the right then in the number157 one is right it should be to the left in 841 8and 1 are in the wrong position 8 - right 1 - left then in the number 624 the number 4 is right but in the wrong position it should be in the middle the answer is digit 1,8,4
