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katen-ka-za [31]
2 years ago
8

If the critical z-value for a hypothesis test... If the critical z-value for a hypothesis test equals 2.45, what value of the te

st statistic would provide the least chance of making a Type I error?
Mathematics
1 answer:
schepotkina [342]2 years ago
8 0

Answer: z score = 0.00714

Step-by-step explanation: the value of test statistics is gotten using the standard normal distribution table.

Z= 2.45 has area to the left (z<2.45) and area to the right (z>2.45).

Level of significance α is the probability of committing a type 1 error. The area under the distribution is known as the rejection region and it is the area towards the right of the distribution.

The table I'm using is towards the left of the distribution.

But z>2.45 + z<2.45 = 1

z> 2.45 = 1 - z<2.45

But z < 2.45 = 0.99286

z > 2.45 = 1 - 0.99286

z >2.45 = 0.00714

Hence the test statistics that would produce the least type 1 error is 0.00714

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Which of the following measurements results in the largest circle?
AnnZ [28]

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1 year ago
Write the first four terms of the sequence defined by An=20-30(n-1)
monitta

The first four terms of sequence is 20, -10, -40, -70

<em><u>Solution:</u></em>

Given that we have to find the first four terms of sequence

<em><u>Given recursive formula is:</u></em>

a_n = 20 - 30(n-1)

<em><u>To find the first term, substitute n = 1</u></em>

a_1 = 20-30(1-1)\\\\a_1 = 20-30(0)\\\\a_1 = 20

Thus the first term of sequence is 20

<em><u>To find the second term, substitute n = 2</u></em>

a_2 = 20-30(2-1)\\\\a_2 = 20-30(1)\\\\a_2 = 20-30\\\\a_2 = -10

Thus the second term of sequence is -10

<em><u>To find the third term, substitute n = 3</u></em>

a_3 = 20-30(3-1)\\\\a_3 = 20-30(2)\\\\a_3 = 20-60\\\\a_3 = -40

Thus the third term of sequence is -40

<em><u>To find the fourth term, substitute n = 4</u></em>

a_4 = 20-30(4-1)\\\\a_4 = 20-30(3)\\\\a_4 = 20-90\\\\a_4 = -70

Thus the first four terms of sequence is 20, -10, -40, -70

3 0
3 years ago
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