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joja [24]
3 years ago
13

WIll give brainliest Use the information given to answer the question.

Mathematics
1 answer:
MaRussiya [10]3 years ago
7 0

Answer:

x²-12x+36

Step-by-step explanation:

an expression in the form (a-b)² is expanded to the form a²-2ab+b²

you can also expand it to (x-6)×(x-6) then multiply the first term by the first the outer term by the outer term the inner term by the inner term and the last term by the last term (foil)

the first terms are x and x = x² the outer terms are x and -6 = -6x the inner terms are also x and -6 = -6x

the last terms are 6 and 6 = 36

adding all the four products =

x²-12x+36

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The manager of a supermarket would like to determine the amount of time that customers wait in a check-out line. He randomly sel
garri49 [273]

Complete question:

The manager of a supermarket would like to determine the amount of time that customers wait in a check-out line. He randomly selects 45 customers and records the amount of time from the moment they stand in the back of a line until the moment the cashier scans their first item. He calculates the mean and standard deviation of this sample to be barx = 4.2 minutes and s = 2.0 minutes. If appropriate, find a 90% confidence interval for the true mean time (in minutes) that customers at this supermarket wait in a check-out line

Answer:

(3.699, 4.701)

Step-by-step explanation:

Given:

Sample size, n = 45

Sample mean, x' = 4.2

Standard deviation \sigma = 2.0

Required:

Find a 90% CI for true mean time

First find standard error using the formula:

S.E = \frac{\sigma}{\sqrt{n}}

= \frac{2}{\sqrt{45}}

= \frac{2}{6.7082}

SE = 0.298

Standard error = 0.298

Degrees of freedom, df = n - 1 = 45 - 1 = 44

To find t at 90% CI,df = 44:

Level of Significance α= 100% - 90% = 10% = 0.10

t_\alpha_/_2_, _d_f = t_0_._0_5_, _d_f_=_4_4 = 1.6802

Find margin of error using the formula:

M.E = S.E * t

M.E = 0.298 * 1.6802

M.E = 0.500938 ≈ 0.5009

Margin of error = 0.5009

Thus, 90% CI = sample mean ± Margin of error

Lower limit = 4.2 - 0.5009 = 3.699

Upper limit = 4.2 + 0.5009 = 4.7009 ≈ 4.701

Confidence Interval = (3.699, 4.701)

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Which value is equivalent to ( 7 • 5 • 2 over 7 • 3) ^2 • ( 5^0 over 2^-3) ^3 • 2^-9
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1. Find the product. Simplify. 13/14 of 10/9. A. 15/42 B. 5/21 C. 2/7 D. 5/6 2. Andy has 5 pots, and each pot can hold 3/8 pound
Rufina [12.5K]

1) Resultant fraction: \frac{65}{63}

2) Total soil: 1\frac{7}{8} pounds

3) Result of the product: \frac{35}{2}

Step-by-step explanation:

1)

In this problem, we want to find the product between the two fractions

\frac{13}{14}

and

\frac{10}{9}

In order to find this product, we have to multiply the numerators of each fraction and the denominators of each fraction. We get:

\frac{13}{14}\cdot \frac{10}{9}=\frac{13\cdot 10}{14\cdot 9}=\frac{130}{126}

Now we simplify, dividing both numerator and denominator by 2:

\frac{130/2}{126/2}=\frac{65}{63}

And the fraction cannot be further simplified.

2)

Here we have:

n = 5 (number of pots that Andy has)

s=\frac{3}{8} (amount of soil (in pounds) that each pot can contain)

In order to find the amount of soil that Andy needs to fill all the pots, we have to multiply the number of pots (n) by the amount of soil that each pot can contain (s).

If we do so, we find:

t=n \cdot s = 5 \cdot \frac{3}{8}=\frac{5\cdot 3}{8}=\frac{15}{8}

Which can be rewritten as a mixed fraction as:

\frac{15}{8}=\frac{8+7}{8}=\frac{8}{8}+\frac{7}{8}=1\frac{7}{8}

3)

Here we want to find the result of the following product:

4\frac{2}{3}\cdot 3\frac{3}{4}

In order to do so, we first have to rewrite each fraction as an improper fraction.

For the 1st fraction:

4\frac{2}{3}=\frac{4\cdot 3+2}{3}=\frac{12+2}{3}=\frac{14}{3}

For the 2nd fraction:

3\frac{3}{4}=\frac{3\cdot 4+3}{4}=\frac{12+3}{4}=\frac{15}{4}

Now we can finally find the product of the two fractions:

\frac{14}{3}\cdot \frac{15}{4}=\frac{14\cdot 15}{3\cdot 4}=\frac{210}{12}=\frac{35}{2}

Where in the last step, we divide both the numerator and the denominator by 6.

Learn more about fractions:

brainly.com/question/605571

brainly.com/question/1312102

#LearnwithBrainly

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ROUND 43.0810194943 TO THE NEAREST TEN-THOUSANDTH HELP!
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43.0810
Since the hundred thousandths is a 1 which is less than a 5, you have to round down.
3 0
3 years ago
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