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joja [24]
3 years ago
13

WIll give brainliest Use the information given to answer the question.

Mathematics
1 answer:
MaRussiya [10]3 years ago
7 0

Answer:

x²-12x+36

Step-by-step explanation:

an expression in the form (a-b)² is expanded to the form a²-2ab+b²

you can also expand it to (x-6)×(x-6) then multiply the first term by the first the outer term by the outer term the inner term by the inner term and the last term by the last term (foil)

the first terms are x and x = x² the outer terms are x and -6 = -6x the inner terms are also x and -6 = -6x

the last terms are 6 and 6 = 36

adding all the four products =

x²-12x+36

You might be interested in
X*2/5=3/20 what si it nowwwwwwwwwwwwwwwwwwwww
gladu [14]

Answer: x = 11/20 = 0.550

Step-by-step explanation:

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                    x-2/5-(3/20)=0  

Step by step solution :

Step  1  :

            3

Simplify   ——

           20

Equation at the end of step  1  :

       2      3

 (x -  —) -  ——  = 0  

       5     20

Step  2  :

           2

Simplify   —

           5

Equation at the end of step  2  :

       2      3

 (x -  —) -  ——  = 0  

       5     20

Step  3  :

Rewriting the whole as an Equivalent Fraction :

3.1   Subtracting a fraction from a whole

Rewrite the whole as a fraction using  5  as the denominator :

         x     x • 5

    x =  —  =  —————

         1       5  

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

3.2       Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

x • 5 - (2)     5x - 2

———————————  =  ——————

     5            5    

Equation at the end of step  3  :

 (5x - 2)     3

 ———————— -  ——  = 0  

    5        20

Step  4  :

Calculating the Least Common Multiple :

4.1    Find the Least Common Multiple

     The left denominator is :       5  

     The right denominator is :       20  

       Number of times each prime factor

       appears in the factorization of:

Prime  

Factor   Left  

Denominator   Right  

Denominator   L.C.M = Max  

{Left,Right}  

5 1 1 1

2 0 2 2

Product of all  

Prime Factors  5 20 20

     Least Common Multiple:

     20  

Calculating Multipliers :

4.2    Calculate multipliers for the two fractions

   Denote the Least Common Multiple by  L.C.M  

   Denote the Left Multiplier by  Left_M  

   Denote the Right Multiplier by  Right_M  

   Denote the Left Deniminator by  L_Deno  

   Denote the Right Multiplier by  R_Deno  

  Left_M = L.C.M / L_Deno = 4

  Right_M = L.C.M / R_Deno = 1

Making Equivalent Fractions :

4.3      Rewrite the two fractions into equivalent fractions

Two fractions are called equivalent if they have the same numeric value.

For example :  1/2   and  2/4  are equivalent,  y/(y+1)2   and  (y2+y)/(y+1)3  are equivalent as well.

To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.

  L. Mult. • L. Num.      (5x-2) • 4

  ——————————————————  =   ——————————

        L.C.M                 20    

  R. Mult. • R. Num.       3

  ——————————————————  =   ——

        L.C.M             20

Adding fractions that have a common denominator :

4.4       Adding up the two equivalent fractions

(5x-2) • 4 - (3)     20x - 11

————————————————  =  ————————

       20               20    

Equation at the end of step  4  :

 20x - 11

 ————————  = 0  

    20    

Step  5  :

When a fraction equals zero :

5.1    When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

 20x-11

 —————— • 20 = 0 • 20

   20  

Now, on the left hand side, the  20  cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :

  20x-11  = 0

Solving a Single Variable Equation :

5.2      Solve  :    20x-11 = 0  

Add  11  to both sides of the equation :  

                     20x = 11

Divide both sides of the equation by 20:

                    x = 11/20 = 0.550

One solution was found :

                  x = 11/20 = 0.550

7 0
3 years ago
How many solutions does the equation have? 7x +3 - x=3(1 + 2x) (A) 0 (B) 1. (C) infinitely many​
tekilochka [14]

Answer:

C) Infinitely many

Step-by-step explanation:

7x+3-x=3(1+2x)

6x+3=3+6x

Subtract 3 from both sides

6x = 6x

Infinitely many solutions

5 0
3 years ago
How many hours he worked
Bogdan [553]
8.50x+100=308.25
subtract 100 from both sides
8.5x = 208.25
divide 8.5 from both sides
x= 24.5 hours worked
4 0
3 years ago
Help me please:(<br><br> basically 50 points
dybincka [34]

Answer:

can you zoom in on the picture!

Step-by-step explanation:

PLEASE give me brainliest i never got it before!!!

7 0
3 years ago
The waiting times between a subway departure schedule and the arrival of a passenger are uniformly distributed between 0 and 8 m
rusak2 [61]

Answer:

0.59375

Step-by-step explanation:

In a uniform distribution the probability that the time t is greater than any given value, X, is:

P(t\geq X)=1-\frac{X}{b-a}

In this problem, the limits of the distribution are a = 0 and b = 8 minutes.

For X =3.25 minutes:

P(t\geq 3.25)=1-\frac{3.25}{8-0} \\P(t\geq 3.25)=0.59375

The probability that a randomly selected passenger has a waiting time greater than 3.25 minutes is 0.59375.

8 0
3 years ago
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