Let us assume the cost of 1 apple = x dollars
Let us also assume the cost of 1 pear = y dollars
Then we can form two equations from the details given in the question. Based on those details the required answer to the question can be easily deduced.
3x + 8y = 14.50
And
6x + 4y = 14
Dividing both sides of the equation by 2 we get
3x + 2y = 7
2y = 7 - 3x
y = (7 - 3x)/2
Putting the value of y from the second equation in the first equation we get
3x + 8y = 14.50
3x + 8[(7 - 3x)/2] = 14.50
3x + 4 (7 - 3x) = 14.50
3x + 28 - 12x = 14.50
- 9x = 14.50 - 28
- 9x = - 13.5
9x = 13.5
x = 13.5/9
= 1.5
Putting the value of x in the second equation we get
6x + 4y = 14
(6 * 1.5) + 4y = 14
9 + 4y = 14
4y = 14 - 9
4y = 5
y = 5/4
= 1.25
So we can find from the above deduction that the cost of 1 apple is 1.5 dollars and the cost of 1 pear is 1.25 dollars
Then
Cost of 2 apples = 2 * 1.5 dollars
= 3.0 dollars
So the cost of 2 apples is $3 and the cost of 1 pear is $1.25.
Answer: balut 3 to 4
Step-by-step explanation:
Hey there!
-8/-4
= 8/4
= -8 ÷ -4
= 8 ÷ 4
= 2
Therefore, your answer is:
Option B. 2
Good luck on your assignment & enjoy your day!
~Amphitrite1040:)
The answer for B is: 40 - (7.50 x 4) = 10 Because 7.50 x 4 = 30 and 40 - 30 = 10 So they are left with $10 after paying for the tickets
The answer for C is: Miguel and his 3 friends started with $40 and had a fee of $7.50 for each ticket and there are 4 people. 4 x 7.50 = 30 and 40 - 30 = 10 so they are left with $10 to spend on snacks and other stuff!
Idk the answer for D sorry about that!
Hope this helps!
Answer:
Step-by-step explanation:
In Δ PQS and ΔPQT
∠QPS = ∠RPT {Common angle}
∠PSQ = ∠PTR = 90° {QS & RT are altitude}
QS = RT {given}
ΔPQS ≅ ΔPRT {A A S congruent}
PQ = PS {CPCT}
So, PQR is an isosceles triangle.
9)
a) Flas card (I) and (iii) are congruent.
b) A S A congruent
c) BC ≅ RP
