You will not be able to find the mean from a histogram. The reason is that histograms are special bar graphs that graph data that fall into a range/interval. For example, you would create bars based on what data might fall into 0-9, 10-19, 20-29, 30-39, etc...

With intervals, we do not know the exact data points. They just fall into a range.

4 0

3 years ago

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Find w + y + y + z <br><br><br> someone pls help

Anit [1.1K]

Answer:

300

Step-by-step explanation:

30+30+w+x+y+z = 360 (all angles round a point add up to 360)

Simplifying :

60 + w+x+y+z = 360

Subtracting 60 from both sides :

w+x+y+z = 300

Hope this helped and brainliest ?

4 0

2 years ago

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the Johnsons want to cover their backyard with new grass their backyard is rectangular with a length of 3x - 2 feet and a width

Andre45 [30]

<h2>Hello!</h2>

The answer is:

The area that the want to cover with new grass will be:

$Area_{grass}=8x^{2} -12x-22$

If we want to calculate what is the ara of the region of the backyard that they want to cover with new grass, we need to calculate the area of the backyard, calculate the area of the swimming pool and its patio, and the last step is to subtract the area of the swimming pool and its patio to the total area of the backyard.

So, to calculate the areas, we need to use the following formula:

$Area=Length*Width$

Also, we need to remember how the distributive property works, since we are going to need it.

We have that:

$(a+b)(c+d)=ac+ad+bc+bd$

We are given the following information:

For the backyard we have:

$Length=3x-2\\Width=3x+1$

For the swimming pool and its patio:

Since there it's not mentioned, let be the first expression the length, and the second one, the width.

$Length=x+4\\Width=x+5$

Then, calculating we have:

Backyard:

$Area_{backyard}=(3x-2)*(3x+1)=9x^{2}+3x-6x-2=9x^{2}-3x-2$

Swimming pool and patio:

$Area_{swimmingpool}=(x+4)*(x+5)=x^{2}+5x+4x+20=x^{2}+9x+20$

Now, calculating the area that they want to cover with new grass, we have:

$Area_{grass}=Area_{backyard}-Area_{swimmingPool}\\\\Area_{grass}=(9x^{2}-3x-2)-(x^{2}+9x+20)\\\\Area_{grass}=9x^{2} -x^{2} -3x-9x-2-20\\\\Area_{grass}=8x^{2} -12x-22$

Hence, we have that the area that the want to cover with new grass will be:

$Area_{grass}=8x^{2} -12x-22$

Have a nice day!

3 0

3 years ago