Factor the following expression: x^2-4x+5
1 answer:
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Step-by-step explanation:
al nth term:
numerator:
denominator:
so nth term :
b). 1; 11; 27; 49
first difference: 10; 16; 22
second difference :6
formula for 1st difference:3a+b
formula for 2nd difference:2a
Therefore:
2a=6
a=3
3a+b=10
sub in a
3(3)+b=10
9+b=10
b=1
sub into quadratic formula
So Tn:
#4
White block(s) = 2
Red block(s) = 1
Purple block(s) = 3
Total = 2 +1 + 3 = 6 blocks
a) P(white) =
P(red) =
P(purple) =
b)Not white block:
1 -
OR 
Because, when they say no white blocks, we simply do not count them and add the rest to find that probability without white blocks.
c) The probability stays the same: lets say now we have
4 white blocks, 2 red, and 6 purple, total will be 12
P(white)=
which is still
d) We get two more blocks in the numerator: lets say we have 4 white blocks, 3 red, 5 purple (after adding 2 of each color), total will be 12
P(purple)=
(im not quite sure if my explanation here helps you though)
e) 1 more of white and purple, 5 more of red
white = 3, purple = 4, red = 6, total = 12
(you can either add 2 to white or purple but make sure you add 5 of red)
P(red)=
= 
White block(s) = 2
Red block(s) = 1
Purple block(s) = 3
Total = 2 +1 + 3 = 6 blocks
a) P(white) =
P(red) =
P(purple) =
b)Not white block:
1 -
Because, when they say no white blocks, we simply do not count them and add the rest to find that probability without white blocks.
c) The probability stays the same: lets say now we have
4 white blocks, 2 red, and 6 purple, total will be 12
P(white)=
d) We get two more blocks in the numerator: lets say we have 4 white blocks, 3 red, 5 purple (after adding 2 of each color), total will be 12
P(purple)=
(im not quite sure if my explanation here helps you though)
e) 1 more of white and purple, 5 more of red
white = 3, purple = 4, red = 6, total = 12
(you can either add 2 to white or purple but make sure you add 5 of red)
P(red)=