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kicyunya [14]
3 years ago
13

Use <, >, or = to compare these numbers. 3.08m and 3.8m

Mathematics
2 answers:
andrew11 [14]3 years ago
5 0
Your answer would be =  because u basically take the 0 out of 3.08 and then it would be 3.8 hope i helped
dolphi86 [110]3 years ago
4 0
This will be
3.08<3.8 or
3.8>3.08.
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One inch is equivalent to 2.54 centimeters. How many inches are in 50.8 centimeters
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A. from 67.86 all the way to the end. (67.86 is not filled)
b. $67.86,
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    $70.00(values equal to or greater than $67.86.)
c. There are many values that represent this inequality.(values equal to or greater than $67.86)

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3 years ago
What will an investment of 6000 Euro at 7% p.a compound interest amount to after 5 years if the interest is compounded:
Over [174]
S = P[1 + (r / m)]^(m * t) 

S = ? 

P = 6000 euro 

r = 0.07 

m = 12 

t = 5 

S = 6000[1 + (0.07 / 12)]^(12 * 5) 

S = 6000(1.00583)^(60) 

S = 6000(1.4176...) 

<span>S = 8505.75 euro

---------------------------

You can now do the rest which is anually and quarterly.</span>
5 0
3 years ago
If f(x) = sin(x/2), then there exists a number c in the interval pie/2 &lt; x &lt; 3pie/2 that satisfies the conclusion of the m
elena-14-01-66 [18.8K]
For the answer to the question above, 
The mean value theorem states the if f is a continuous function on an interval [a,b], then there is a c in [a,b] such that: 
<span>f ' (c) = [f(b) - f(a)] / (b - a) </span>
<span>
So [f(a) - f(b)] ( b - a ) = [sin(3pi/4) - sin(pi/4)]/pi </span>
= [sqrt(2)/2 - sqrt(2)/2]/pi = 0 
So for some c in [pi/2, 3pi/2] we must have f ' (c) = 0 

In general f ' (x) = (1/2) cos (x/2) 
We ask ourselves for what values x in [pi/2, 3pi/2] does the above equation equal 0. 
0 = (1/2) cos (x/2) 
0 = cos (x/2) 
x/2 = ..., -5pi/2, -3pi/2, -pi/2, pi/2, 3pi/2, 5pi/2,... 
x = ..., -5pi, -3pi, -pi, pi. 3pi, 5pi, .... 
and x = pi is the only solution in our interval. 

So c = pi is a solution that satisfies the conclusion of the MVT
3 0
3 years ago
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