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Gelneren [198K]
3 years ago
11

PLEASEEEE HELP URGENT

Mathematics
1 answer:
kotegsom [21]3 years ago
7 0

Answer:

7.1 cm

Step-by-step explanation:

The diagonal of a cube connects two opposite corners.

You can use the diagonal of a cube in a right triangle in which it is the hypotenuse. The legs of the triangle are a diagonal of a face and an edge.

Let the length of the edge be s.

a^2 + b^2 = c^2

s^2 + 10^2 = (\sqrt{150})^2

s^2 + 100 = 150

s^2 = 50

s = \sqrt{50}

s = 5\sqrt{2}

s = 7.1

Answer: 7.1 cm

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Answer:

76%

Step-by-step explanation:

Times the decimal by 100 to get a percent

basically moving the decimal 2 spaces to the right.

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3 years ago
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MaRussiya [10]
I might be wrong but 9

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2 years ago
12x to the power of 5 divided by 3xto the power of 2
meriva

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Which functions are symmetric with respect to the y axis<br>​
Inessa05 [86]

Answer:

A, B, and D

Step-by-step explanation:

Only the functions that have x by itself between the absolute value signs (A, B, and D) are symmetric with respect to the y-axis .

Placing a constant outside the absolute value signs moves the function up or down the y-axis but retains the symmetry.

Adding a constant inside the absolute value signs (as in C and E) moves the axis of symmetry to the left or right of the y-axis.

In the diagram, both A and B are symmetric with respect to the y-axis, but C has been shifted three units to the left.

4 0
3 years ago
Find the area of the region in two ways. a. Using integration with respect to x. b. Using geometry. 9-x
Natali [406]

Answer: hello your question is incomplete attached below is the complete question

answer :

a)   \int\limits^3_0 {(10-x)-(x+4)} \, dx     ( option D )

b) A =  1/2 (6)(3)   ( option B )

c) Area of shaded region = 9

Step-by-step explanation:

<u>a) Using integration with respect to x </u>

Area =   \int\limits^7_4 {(y-4)} \, dy + \int\limits^a_7 {(10-y)} \, dy         ( note a = 10 )

          = y^2/2 - 4y |⁷₄  + 10y - y^2/2 |¹⁰₇

          = 33/2 - 12 + 30 - 51/2   = 9

hence the best integral from the options attached is option D

\int\limits^3_0 {(10-x)-(x+4)} \, dx

= [ 10x - x^2 /2 - x^2/2 - 9x ] ³₀

= 30 - 9/2 - 9/2 - 12  = 9

<u>b) Using Geometry </u>

Area = 1/2 * base * height

        = 1/2 * 6 * 3

        = 9

7 0
3 years ago
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