Let d be the number of days and h be the height
h = 13 + 0.6d
Answer: (a) h = 13 + 0.6d
Given height = 0.208m, find d:
0.208m = 20.8 cm
20.8 = 13 + 0.6d
0.6d = 20.8 - 13 = 7.8
d = 7.8 ÷ 0.6 = 13
Answer: (b) 13 days
Answer:
the picture is not clear can you take a new picture so I can help.
Step-by-step explanation:
Taking the derivative of 7 times secant of x^3:
We take out 7 as a constant focus on secant (x^3)
To take the derivative, we use the chain rule, taking the derivative of the inside, bringing it out, and then the derivative of the original function. For example:
The derivative of x^3 is 3x^2, and the derivative of secant is tan(x) and sec(x).
Knowing this: secant (x^3) becomes tan(x^3) * sec(x^3) * 3x^2. We transform tan(x^3) into sin(x^3)/cos(x^3) since tan(x) = sin(x)/cos(x). Then secant(x^3) becomes 1/cos(x^3) since the secant is the reciprocal of the cosine.
We then multiply everything together to simplify:
sin(x^3) * 3x^2/ cos(x^3) * cos(x^3) becomes
3x^2 * sin(x^3)/(cos(x^3))^2
and multiplying the constant 7 from the beginning:
7 * 3x^2 = 21x^2, so...
our derivative is 21x^2 * sin(x^3)/(cos(x^3))^2
Answer:
Can you post the picture pls
Step-by-step explanation:
Wait how would you even do this?
