All categories

3 years ago

Find the 11th term from the end in the AP 56, 63, 70,..., 329

1 answer:

4 0

Given sequence:
56, 63, 70,..., 329
First find the common difference:
d=a2-a1
d=63-56
d=7
Formula:
an=a1+(n-1)d
First find the number of terms.
329=56+(n-1)7
329=56+7n-7
329=49+7n
280=7n
40=n
or
n=40
We have to find 40-11=29 th term ( 11 th term from the end)
a29= 56+(29-1)7
a29=56+(28)7
a29=56+196
a29=252

Answer: 252 is 11th term from the end.

You might be interested in

One number is 3 times another. If the sum of the two numbers is 15, find the two numbers.

gregori [183]

Answer:

15/4 and 45/4

Step-by-step explanation:

Let x and y be the numbers

x = 3y

x+ y = 15

Substitute the first equation in to the second equation

3y+y = 15

4y = 15

y = 15/4

x = 3(15/4)

x = 45/4

The two numbers are 15/4 and 45/4

8 0

2 years ago

Read 2 more answers

19.

vichka [17]

Answer:

168

Step-by-step explanation:

Sum the parts of the ratio, 6 + 7 = 13 parts

Divide the total number of students by 13 to find the value of one part of the ratio.

364 ÷ 13 = 28 ← value of 1 part of the ratio, thus

number of girls = 6 × 28 = 168

3 0

3 years ago

If the cash price of a truck is $25,000 and a business

olasank [31]

Answer:

500$

finaced= provide funding for

5 0

3 years ago

The tee for the sixth hole on a golf course is 305 yards from the tee. On that hole, Marsha hooked her ball to the left, as sket

EleoNora [17]

Answer:

Correct answer is option D. 96.4 yd.

Step-by-step explanation:

Please refer to the attached figure for labeling of the given diagram.

ABC is a triangle with the following labeling:

A is the hole, B is the Tee and C is the point where the ball is.

Sides are labeled as:

$a =255\ yd\\c = 305\ yd\\\angle B =17^\circ$

To find:

Side $b = ?$

Solution:

Here, we have one angle and two sides . Third side of the triangle is to be found opposite to the given angle.

We can use cosine formula here to find the value of the unknown side.

$cos B = \dfrac{a^{2}+c^{2}-b^{2}}{2ac}$

Putting all the values:

$cos 17 = \dfrac{255^{2}+305^{2}-b^{2}}{2\times 255\times 305}\\\Rightarrow 0.956 = \dfrac{65025+93025-b^{2}}{155550}\\\Rightarrow 148753.2= 158050-b^{2}\\\Rightarrow b^{2}= 158050-148753.2\\\Rightarrow b^{2}= 9296.795\\\Rightarrow b= 96.42\ yd$

So, the distance between the Ball and hole is 96.42 yd

Correct answer is option D. 96.4 yd.

8 0

2 years ago

A cooking show currently has about 223,00 regular viewers. The number of regular viewers has been decreasing at a rate of 4.7% p

Mazyrski [523]

The best prediction for the number of regular spectators that the program will have in 6 years is obtained with the following formula:
Pf = Po×(1-b) ^ t
Where:
Pf = final population
Po = initial population
b = decrease rate
t = timpo in years
So:
Pf = 223.00×(1-0.047) ^ 6
Pf = 167,056
The answer is the last option.

5 0

3 years ago