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Reil [10]
3 years ago
10

PLEASE HELP ASAP

Mathematics
1 answer:
sergey [27]3 years ago
5 0
The answer would be D
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How to represent y=5x+40 with a table
Tems11 [23]
1 | 2.5
2 | 5
3 | 10
4 | 20
5 | 40
6 | 80
7 | 160
8 | 320
9 | 640

Hopes this helps!!!
5 0
3 years ago
Read 2 more answers
HELP! will mark BRAINILEST !
Sedbober [7]
I like A as the best one

420 = 100*price - (fixed costs)
220 = 60*price - (fixed costs)

If we subtract one from the other one, we get 200 = 40*price, price = 5
that said, fixed costs are 500 - 420 = 80

Now if we move -220 to the right in Answer A, we'll get:

y = 5x -300 + 220 = 5x - 80

So it looks like A describes the model best
6 0
3 years ago
Graph a line that contains the point (-5, -6) and has a slope of 2/3.
OlgaM077 [116]

Answer:

I think this will help

Step-by-step explanation:

Make a point at(-5,-6) then go up two boxes and right three boxes.

4 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%20%7B75%7D%5E%7B2%7D%20%2B%2025%20-%20750" id="TexFormula1" title=" {75}^{2} + 25 - 750" alt=
frez [133]
your answer is 4900
3 0
3 years ago
If the rate of decrease for the partial pressure of N2H4 in a closed reaction vessel is 76 torr/h , what is the rate of change f
fiasKO [112]

The reaction is missing and it's ;

N2H4 + H2 ---> 2NH3

It asks for the total pressure too.

Answer:

A) Rate of change for NH3 = 152 torr/h

B) The total pressure in the vessel will remain the same.

Step-by-step explanation:

N2H4 + H2 ---> 2NH3

1 mole of N2H4 yields 2 moles of NH3.

From the question, the rate given for N2H4 is 76 torr/h.

Thus, The rate of change for NH3 will be = 2 x 76 = 152 torr/h

Now, on the reaction side, 1 mole of N2H4 reacts with 1 mole of H2. So we have 2 moles on the left hand side.

While on the product side, 2 moles of NH3 are produced.

So the total pressure will remain the same because for every 2 moles on the reaction side, 2 moles are gotten on the product side.

3 0
3 years ago
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