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PSYCHO15rus [73]
2 years ago
10

The product of 2 mixed numbers that are each between 4 and 5 is between 16 and 25. true or false?

Mathematics
1 answer:
wel2 years ago
8 0

True.


Extra letters: buqwdusaouboaskjcbqohiohaiqouvhsbxcjk

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Round to the nearest tenth 72​
Drupady [299]

Answer:

It would be 70

Step-by-step explanation:

Round to the nearest tenth 72​

the answer is 70 why because if you around to the nearest 10 it would be 70.

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A. 42<br> b. 27<br> c. 12<br> d. 18
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True or false the reciprocal of 5 is 1/5<br>シ​
rodikova [14]

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Please help in maths
Readme [11.4K]

The equivalent expressions of 22c + 33d are (a), (c) and (e)

<h3>How to determine the equivalent expressions?</h3>

The expression is given as:

22c + 33d

Factor out 11 from the expression

11(2c + 3d)

Multiply by 1

1 * 11(2c + 3d)

Express 1 as -1 * -1

-1 * -1 * 11(2c + 3d)

Evaluate the product

(-11) * (-2c - 3d)

Also, we have:

22c + 33d

Multiply by 1

(22c + 33d) * 1

Express 1 as 3/3

(22c + 33d) * 3/3

Evaluate the product

(66c + 99d) * 1/3

Hence, the equivalent expressions are (a), (c) and (e)

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7 0
1 year ago
Suppose we want to build a rectangular storage container with open top whose volume is $$12 cubic meters. Assume that the cost o
Snezhnost [94]

Answer:265.25

Step-by-step explanation:

Given

Volume of box=12 m^3

height is 3 times the width

let height, length and breadth be H, L & B

H=3\times B

V=12=L\times B\times H

4=B^2\times L[/tex]

L=\frac{4}{B^2}

Cost of side walls $ 8/m^2

Cost of base $ 12/m^2

Cost of side walls=(2LH+2BH)\cdot 8

Cost of base =12LB

Total cost C=16LH+16BH+12LB

C=48LB+48B^2+12LB

C=\frac{192}{B}+48B^2+\frac{48}{B}

differentiate C w.r.t B to get minimum cost

\frac{\mathrm{d} C}{\mathrm{d} B}=-\frac{192}{B^2}+2\times 48 B-\frac{48}{B^2}

B^3=\frac{240}{2\times 48}

B=1.35 m

H=3\times 1.35=4.07 m

L=2.19 m

C=$ 265.25

3 0
2 years ago
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