The product of 2 mixed numbers that are each between 4 and 5 is between 16 and 25. true or false?

boeing plans to increase its price for jetliners. with a selling price $201.5 million and a cost of $190.1 million, what was the

scoray [572]

so from 190.1 to 201.5 is 201.5 - 190.1 = 11.4.

now, if we take 190.1 as the 100%, what is 11.4 off of it in percentage?

$\bf \begin{array}{ccll} amount&\%\\ \cline{1-2} 190.1&100\\ 11.4&x \end{array}\implies \cfrac{190.1}{11.4}=\cfrac{100}{x}\implies 190.1x=1140 \\\\\\ x=\cfrac{1140}{190.1}\implies x\approx 5.99684$

3 0

3 years ago

Read 2 more answers

Litter such as leaves falls to the forest floor, where the action of insects and bacteria initiates the decay process. Let A be

Travka [436]

Answer:

D = L/k

Step-by-step explanation:

Since A represents the amount of litter present in grams per square meter as a function of time in years, the net rate of litter present is

dA/dt = in flow - out flow

Since litter falls at a constant rate of L grams per square meter per year, in flow = L

Since litter decays at a constant proportional rate of k per year, the total amount of litter decay per square meter per year is A × k = Ak = out flow

So,

dA/dt = in flow - out flow

dA/dt = L - Ak

Separating the variables, we have

dA/(L - Ak) = dt

Integrating, we have

∫-kdA/-k(L - Ak) = ∫dt

1/k∫-kdA/(L - Ak) = ∫dt

1/k㏑(L - Ak) = t + C

㏑(L - Ak) = kt + kC

㏑(L - Ak) = kt + C' (C' = kC)

taking exponents of both sides, we have

$L - Ak = e^{kt + C'} \\L - Ak = e^{kt}e^{C'}\\L - Ak = C"e^{kt} (C" = e^{C'} )\\Ak = L - C"e^{kt}\\A = \frac{L}{k} - \frac{C"}{k} e^{kt}$

When t = 0, A(0) = 0 (since the forest floor is initially clear)

$A = \frac{L}{k} - \frac{C"}{k} e^{kt}\\0 = \frac{L}{k} - \frac{C"}{k} e^{k0}\\0 = \frac{L}{k} - \frac{C"}{k} e^{0}\\\frac{L}{k} = \frac{C"}{k} \\C" = L$

$A = \frac{L}{k} - \frac{L}{k} e^{kt}$

So, D = R - A =

$D = \frac{L}{k} - \frac{L}{k} - \frac{L}{k} e^{kt}\\D = \frac{L}{k} e^{kt}$

when t = 0(at initial time), the initial value of D =

$D = \frac{L}{k} e^{kt}\\D = \frac{L}{k} e^{k0}\\D = \frac{L}{k} e^{0}\\D = \frac{L}{k}$

4 0

3 years ago

Factor out the greatest common factor <br>-5x^2 - 5x^3 - 15x^4

vaieri [72.5K]

Our answer is $-5x^{2} (3x^{2} +x+1)$

Our greatest common factor, or GCF, is $-5x^{2}$ , so when we factor is out, our divide each term by $-5x^{2}$ , we get our answer. To check this, we can multiply the $-5x^{2}$ back across the parenthesis and see if we get the same result as our initial question.

Hope this helped! :))

5 0

3 years ago

A highway had a landslide, where 3,00 cubic yards of material fell on the road, requiring 200 dump truck loads to clear. On anot

Andru [333]

Answer:

2667 dump truck loads

Step-by-step explanation:

To solve this exercise, we must resort to a proportion rule.

Knowing what happened in the first place, how much was needed, a direct proportion will be made with the other accident, be as follows.

Landslide Dump Truck Loads

3 yd ^ 3 -------------------------------------------> 200

40 yd ^ 3 -------------------------------------------> X

X = (40 * 200) / 3

X = 2666.6, that is, for 40 cubic yards of sliding, approximately 2667 dump truck loads are needed.

8 0

3 years ago

A student earns scores of 80, 87, and 82 on the first three of four tests. If the student wants to achieve a quiz average of 85,

aleksandrvk [35]

Answer:

91

Step-by-step explanation:

85= $\frac{80+87+82+x}{4}$ then multiply the 4 over and subtract 80, 87, and 82 to find x which gives you 91

5 0

3 years ago