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3 years ago

Use the quadratic equation y = x2 + 6x + 36.

Mathematics

1 answer:

WINSTONCH [101]3 years ago

3 0

0,36 is vertical
X(0)
Y(36

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Cooper just started a running plan where he runs 8 miles the first week and then

lozanna [386]

He would’ve ran 286 miles in total.

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2 years ago

If G = {(-1, 7),(-8, 2),(0, 0),(6, 6)), then the range of G is

lana66690 [7]

Answer:

$\{0, 2, 6, 7\}$

Step-by-step explanation:

You are given the relation $G = \{(-1, 7),(-8, 2),(0, 0),(6, 6)\}$

This means that

$f(-1)=7\\ f(-8)=0\\f(0)=0\\f(6)=6$

The input values of this relation are $-1,\ -8,\ 0,\ 6$ , so the domain of this relation is $\{-8,-1,0,6\}$

The output values of this relation are $7,\ 2,\ 0,\ 6$ , so the range of this relation is $\{0, 2, 6, 7\}$

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3 years ago

Express the angle in radian measure.<br><br> 200°

kiruha [24]

200deg in radians is 200* pi/180= 3.49 radians hope this helps! Use this conversion for any def to radian measure.

5 0

3 years ago

Read 2 more answers

Find the domain of the function f(x) = – 1x^2 – 2x – 1

navik [9.2K]

Answer:

All real numbers.

Step-by-step explanation:

Since this is a quadratic function, that means the domain is all real numbers.

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3 years ago

An article in Knee Surgery, Sports Traumatology, Arthroscopy, "Arthroscopic meniscal repair with an absorbable screw: results an

igomit [66]

Answer:

Mean = 1.57

Variance=0.31

Step-by-step explanation:

To calculate the mean and the variance of the number of successful surgeries (X), we first have to enumerate the possible outcomes:

1) Both surgeries are successful (X=2).

$P(e_1)=0.90*0.67=0.603$

2) Left knee unsuccessful and right knee successful (X=1).

$P(e_2)=(1-0.9)*0.67=0.1*0.67=0.067$

3) Right knee unsuccessful and left knee successful (X=1).

$P(e_3)=0.90*(1-0.67)=0.9*0.33=0.297$

4) Both surgeries are unsuccessful (X=0).

$P(e_4)=(1-0.90)*(1-0.67)=0.1*0.33=0.033$

Then, the mean can be calculated as the expected value:

$M=\sum p_iX_i=0.603*2+0.067*1+0.297*1+0.033*0\\\\M=1.206+0.067+0.297+0\\\\M=1.57$

The variance can be calculated as:

$V=\sum p_i(X_i-\bar{X})^2\\\\V=0.603(2-1.57)^2+(0.067+0.297)*(1-1.57)^2+0.033*(0-1.57)^2\\\\V=0.603*0.1849+0.364*0.3249+0.033*2.4649\\\\V=0.1115+0.1183+0.0813\\\\V=0.3111$

3 0

3 years ago