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ahrayia [7]
3 years ago
9

What is the missing value to the nearest hundredth?

Mathematics
2 answers:
k0ka [10]3 years ago
3 0
The answer would be : A.85.44
Shalnov [3]3 years ago
3 0
\bf tan(\theta)=12\implies tan^{-1}[tan(\theta)]=tan^{-1}(12)\implies \measuredangle \theta=tan^{-1}(12)

now, assuming the angle is expected in degrees, thus, make sure your calculator is in Degree mode, when getting the inverse tangent
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PLEASE HELP FAST!!!!!
Ivanshal [37]

MALLORY?!

sorry i would answer but i'm having troubles myself!!!!!

7 0
3 years ago
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Can someone please help!
agasfer [191]
“Y” is equal to 9 because you substitute the x which is 2 and then solve from there
7 0
3 years ago
Task 3:
Natalija [7]

Answer:

A.   4.5 ft

B.    4 ft

C.    1 ft

Step-by-step explanation:

If you pretend that h is replacing y and d is replacing x and you would graph the equation, then you would get a parabola that opens down.

You would need to find the vertex of the parabola.  The ordered pairs would be (d, h) instead  of the normal (x, y).  

A.  The maximum height will be the h value of the vertex

B.   Let h = 0 and solve the equation for d.  That will give you distance from the stump that the frog landed.

C.  The distance from the log at the maximum height is the d value of the vertex

So, that is what is needed to be done.

Without me going thru all the work, the vertex is (1, 4.5) and the solutions to the equation when h = 0 are 4, -2  (discard -2 since a distance cannot be negative)

So the answer to A is 4.5 ft.

The answer to B is 4ft.

The answer to C is 1 ft.

Now, can you find the vertex on your own and can you solve the equation when h = 0?  I hope so.  OK?

5 0
3 years ago
Two students are playing a math game. The object of the game is to make the least possible number by arranging the given digits
Misha Larkins [42]

l-75.3l is equal to 75.3 so that's not the smallest number possible.


8 0
4 years ago
Read 2 more answers
QUICCCKKK !!! what is (5x + 7) + (x+2)
Katena32 [7]
I believe the answer would be 6x + 9
3 0
3 years ago
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