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3 years ago

5x - 7(2- 4x) = 8 - 3(6 - 6x) = 9a - 4(2a + 5) =

Mathematics

1 answer:

kati45 [8]3 years ago

8 0

Answer:

the answer to 5x-7(2-4x)= =33x−14

the answer to 8 - 3(6 - 6x) ==18x−10

the answer to 9a - 4(2a + 5) ==a−20

Step-by-step explanation:

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bija089 [108]

The correct answer is 182

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If a 4 x 16 rectangle has the same area as a square, what is the length of a side of the square?

Licemer1 [7]

Answer:

Option D. 8 units

Step-by-step explanation:

step 1

Find the area of rectangle

The area of rectangle is

$A=(4)(16)=64\ units^2$

step 2

Find the length side of the square with the same area of rectangle

The area of a square is

$A=b^2$

where

b is the length side of the square

we have

$A=64\ units^2$

substitute

$64=b^2$

take the square root both sides

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3 years ago

A prairie dog left its burrow 5 feet underground and started digging deeper into the ground. It digs straight down at a constant

SpyIntel [72]

Building and solving an equation to model the situation, it is found that it takes 4 min for the prairie dog to reach 13 feet underground.

Initially, the dog is 5 feet underground.

Each minute, the dog goes 2 more feet underground.

Hence, the underground height of the dog after t seconds is given by:

$h(t) = 5 + 2t$

The time it takes for the dog to reach 13 feet underground is <u>t for which h(t) = 13</u>, hence:

$h(t) = 5 + 2t$

$13 = 5 + 2t$

$2t = 8$

$t = \frac{8}{2}$

$t = 4$

It takes 4 min for the prairie dog to reach 13 feet underground.

A similar problem is given at brainly.com/question/25290003

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2 years ago

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3 years ago

How many extraneous solutions does the equation below have?

aev [14]

Answer:

A solution is said to be extraneous, if it is a zero of the equation, but it does not satisfy the equation,when substituted in the original equation,L.H.S≠R.H.S.

The given equation consisting of variable , m is

$\frac{2 m}{2 m+3} -\frac{2 m}{2 m-3}=1\\\\ 2 m[\frac{1}{2 m+3} -\frac{1}{2 m-3}]=1\\\\ 2 m\times \frac{[2 m-3 -2 m- 3]}{4m^2-9}=1\\\\ -6 \times 2 m=4 m^2 -9\\\\ 4 m^2 +1 2 m -9=0\\\\m=\frac{-12 \pm\sqrt{12^2-4 \times 4 \times (-9)}}{2\times 4}\\\\m=\frac{-12 \pm \sqrt {144+144}}{8}\\\\m=\frac{-12 \pm \sqrt {288}}{8}\\\\m=\frac{-12 \pm 12 \sqrt{2}}{8}\\\\m=\frac{3}{2}\times(-1 \pm \sqrt{2})$

None of the two solution

$m=\frac{3}{2}\times(-1 +\sqrt{2}) and , m=\frac{3}{2}\times(-1 -\sqrt{2})$ , is extraneous.

Here, L.H.S= R.H.S

Option A: 0→ extraneous

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2 years ago

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