All categories

4 years ago

What is the greatest prime you must consider to test whether 7066 is prime?

Mathematics

2 answers:

Liono4ka [1.6K]4 years ago

8 0

Answer:

Step-by-step explanation:

The square root of 7066 is 84.0595....

Therefore the largest number we must test is 84, seeing as now we have proven we do not need to test any numbers greater than 84.0595...

That means, we only need to test prime numbers smaller than 84 to see if they go into 7066.

84 isn't prime. But 83 is prime.

Therefore, the greatest prime that needs to be considered for divisibility is 83.

zepelin [54]4 years ago

5 0

Answer:

The numbers 7066 is not prime .

But we easily know when a number is prime when we divide it by the first prime numbers; 2, 3, 5, 7, 11.

Step-by-step explanation:

It is known with certainty that a number is prime when it is only divisible by and by unity.

But in this case, that number, when divided by other numbers less than the one, shows that when dividing into the remainder, it gives zero, which means that it is not only divisible by itself or by the unit, but also by other numbers.

for example; 7066/2=3533 , the remainder is zero;

You might be interested in

Find the volume of the rectangular prism 7in 7in 6in

goldfiish [28.3K]

Answer:

294

Step-by-step explanation:

7x7=49

49x6=294

area of rectangular prism= length x width x height

4 0

3 years ago

Read 2 more answers

Identify the like terms 3x,4y,4z,5x

Elenna [48]

The like terms are 5x and 3x because they both are apart of the x family !

6 0

3 years ago

At the farmers market a farmer has bunches of radishes for sale. The

stealth61 [152]

Answer:

The probability a random selected radish bunch weighs between 5 and 6.5 ounces is 0.8185

Step-by-step explanation:

The weight of the radish bunches is normally distributed with a mean of 6 ounces and a standard deviation of 0.5 ounces

Mean = $\mu = 6$

Standard deviation = $\sigma = 0.5$

We are supposed to find the probability a random selected radish bunch weighs between 5 and 6.5 ounces i.e.P(5<x<6.5)

$Z=\frac{x-\mu}{\sigma}$

At x = 5

$Z=\frac{5-6}{0.5}$

Z=-2

$Z=\frac{x-\mu}{\sigma}$

At x = 6.5

$Z=\frac{6.5-6}{0.5}$

Z=1

Refer the z table for p value

P(5<x<6.5)=P(x<6.5)-P(x<5)=P(Z<1)-P(Z<-2)=0.8413-0.0228=0.8185

Hence the probability a random selected radish bunch weighs between 5 and 6.5 ounces is 0.8185

6 0

3 years ago

Solve Q²= a(p²-b²)/p in form of y=mx+c

umka2103 [35]

Answer:

We want to rewrite:

q^2 = a*(p^2 - b^2)/p

as a linear equation, in the form:

y = m*x + c

So we start with:

q^2 = a*(p^2 - b^2)/p

we can expand the left side to get:

q^2 = (a/p)*p^2 - (a/p)*b^2

q^2 = a*p - (a/p)*b^2

Now we can ust define:

a*p = c

Then we can replace that to get:

q^2 = -(a/p)*b^2 + c

now we can replace:

q^2 = y

b^2 = x

Replacing these, we get:

y = -(a/p)*x + c

finally, we can replace:

-(a/p) = m

then we got the equation:

y = m*x + c

where:

y = q^2

x = b^2

c = a*p

m = -(a/p)

4 0

3 years ago

Given that (7x-8)/(2x-1)(x-2) Use Partial Fraction Decomposition to Find A and B.

koban [17]

We look for constants a and b such that

$\displaystyle \frac{7x-8}{(2x-1)(x-2)} = \frac a{2x-1} + \frac b{x-2}$

Rewrite all terms with a common denominator and set the numerators equal:

$\displaystyle \frac{7x-8}{(2x-1)(x-2)} = \frac{a(x-2)}{(2x-1)(x-2)} + \frac{b(2x-1)}{(x-2)(2x-1)} \\\\ \frac{7x-8}{(2x-1)(x-2)} = \frac{a(x-2)+b(2x-1)}{(2x-1)(x-2)} \\\\ \implies 7x-8 = a(x-2) + b(2x-1) = (a+2b)x - 2a - b$

Then

a + 2b = 7

-2a - b = -8

Solve for a and b. Using elimination: multiply the first equation by 2 and add it to the second equation:

2 (a + 2b) + (-2a - b) = 2(7) + (-8)

2a + 4b - 2a - b = 14 - 8

3b = 6

b = 2

Then

a + 2(2) = 7 ==> a = 3

and so

$\displaystyle \frac{7x-8}{(2x-1)(x-2)} = \frac 3{2x-1} + \frac 2{x-2}$

7 0

3 years ago

Read 2 more answers